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Yakvenalex [24]

3 years ago

6

_____ is the degree of attraction of one atom for the valence electrons of another atoms. Electronegativity Ionization energy Co

valent bonding Ionic bonding

2 answers:

ANEK [815]3 years ago

5 0

Electro negativity is correct!

yan [13]3 years ago

4 0

<span>Electronegativity maybe.......</span>

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Cellulose could provide an abundant and cheap form of glucose for humans. Why is cellulose not a source of nutrients for humans?

mojhsa [17]

Answer:

Option (c).

Explanation:

Cellulose is one of the most important carbohydrate of the plant that provide structural framework to the plant cells. Cellulose is made of the monomer of the glucose that are linked through the beta glycosidic linkages.

Although cellulose contains large number of glucose but it cannot be used as the nutrient source for humans. Humans and other vertebrates lacks the enzyme cellulase that is required for the digestion of cellulose. Cellulose cannot be broken down in the human body.

Thus, the correct answer is option (c).

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3 years ago

Why is the metric system the preferred system of measurement for science

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In is a lot easier because it uses 10s.

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3 years ago

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user100 [1]

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2 years ago

When a paper towel absorbs water, is it a physical or chemical change?

Nonamiya [84]

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It is a physical change.

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2 years ago

Consider the reaction: P(s) + 5/2 Cl2(g)PCl5(g) Write the equilibrium constant for this reaction in terms of the equilibrium con

Pani-rosa [81]

Answer: The equilibrium constant for the overall reaction is $K_a\times K_b$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios.

a) $P(s)+\frac{3}{2}Cl_2(g)\rightarrow PCl_3(g)$

$K_a=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}$

b) $PCl_3(g)+Cl_2(g)\rightarrow PCl_5(g)$

$K_b=\frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

For overall reaction on adding a and b we get c

c) $P(s)+\frac{5}{2}Cl_2(g)\rightarrow PCl_5(g)$

$K_c=\frac{[PCl_5]}{[Cl_2]^\frac{5}{2}}$

$K_c=K_a\times K_b=\frac{[PCl_3]}{[Cl_2]^{\frac{3}{2}}}\times \frac{[PCl_5]}{[Cl_2]\times [PCl_3]}$

The equilibrium constant for the overall reaction is $K_a\times K_b$

4 0

2 years ago