<h3>Answer:</h3>
C6H12O6
Explanation:
To find empirical formular you write out the element
Carbon Hydrogen Oxygen
3.96 769 5.28
then u althrough divide by their atomic numbers
3.96÷ 12 769÷1 5.28÷16
=0.33 =769 =0.33
also divide althrough by the lowest number
the lowest number is 0.33 so we use it to divide
0.33÷0.33. 769÷0.33. 0.33÷0.33
= 1 = 2 = 1
empirical formular= CH2O
To find the Molecular formular
Molecular number = molar mass
(CH2O)n = 182
(12+1×2+16)n = 182
30n = 182
n = 6
therefore the Molecular formular is C6H12O6
Answer:
the energy should be potential
it may be C. did you get the right answer so you could study it?
mole fraction of potassium bromide = 0.23
Explanation:
We define mole fraction of a specific compound in a mixture as:
mole fraction of a compound = number of moles of the compound / total number of moles
in our case we have:
number of moles of potassium bromide = 3 moles
total number of moles = number of moles of potassium bromide + number of moles of water
total number of moles = 3 + 10 = 13 moles
mole fraction of potassium bromide = 3 / 13 = 0.23
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mole fraction
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