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xeze [42]
3 years ago
12

Is the following conditional true or false? If it is true, explain why. If it is false, give a counterexample

Mathematics
1 answer:
Schach [20]3 years ago
6 0
Well I would solve it but where's the problem?
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SBC is an isosceles triangle with main vertex S.
stira [4]

Answer + Step-by-step explanation:

1) D be the symmetric of B with respect to C then CD = BC

A the symmetric of C with respect to B then AB = BC

We obtain :

CD = BC

AB = BC

Then AB = CD

2) m∠SBA = 180 - SBC = 180 - SCB = m∠SCD

3) we have :

BA = CD

BS = CS

m∠SBA = m∠SCD

Then

the triangles SBA and SCD are congruent

4)

the triangles SBA and SCD are congruent Then SA = SD

Therefore SAD is an isosceles triangle.

4 0
2 years ago
Jan left her home and drove for 5.2 hours due north at a rate of 60 miles per hour. After visiting a friend, she drove due south
Andreyy89

Answer:

180 miles

Step-by-step explanation:

Going North

<em><u>Formula</u></em>

d = r * t

<em><u>Givens</u></em>

r = 60 mph

t = 5.2 hours

d = ?

<em><u>Solution</u></em>

d = 5.2 * 60 = 312 miles north

Going South

<em><u>Givens</u></em>

r = 55 mph

t = 2.4 hours

<em><u>Solution</u></em>

d = r * t

d = 55 * 2.4

d = 132

Distance from home

Formula: Distance from home = Distance North - Distance South

Distance North = 312  -   132 = 180 miles

4 0
3 years ago
Read 2 more answers
For the inverse variation equation p = StartFraction 8 Over V EndFraction, what is the value of V when p = one-half?
likoan [24]

Answer:

V=16

Step-by-step explanation:

We are given that an inverse variation

p=\frac{8}{V}

We have to find the value of V when p=1/2

To find the value of V we will substitute the value of p

Substitute the value of p

Then, we get

\frac{1}{2}=\frac{8}{V}

\frac{V}{2}=8

Using multiplication property of equality

V=8\times 2

Using multiplication property of equality

V=16

Hence, the value of V=16

3 0
3 years ago
What is 56,902 in expanded form?
mariarad [96]
56,900 but I'm only 50% sure I don't know about the other 50% sorry If its wrong.
3 0
3 years ago
Read 2 more answers
Please prove it for me​
grigory [225]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

tanx = \frac{1}{cotx}

Consider the left side

\frac{cotA-1}{cotA+1} ← divide terms on numerator/denominator by cotA

= \frac{\frac{cotA}{cotA}-\frac{1}{cotA}  }{\frac{cotA}{cotA}+\frac{1}{cotA}  }

= \frac{1-tanA}{1+tanA}

= right side , thus proven

7 0
2 years ago
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