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Serjik [45]
3 years ago
9

Explain whyyy????????

Mathematics
2 answers:
bixtya [17]3 years ago
7 0
I think the answer for this question is B
qwelly [4]3 years ago
5 0
These linear functions are in the form: y = ax + b

Plugging in any value of x will give you the value of y, and vice-versa.

The grid says that when x = 0, y = 1.35. And also, when x = 22.5, y = 0.

So you can eliminate half of the possibilities by plugging x = 0 in all the equations.

When x = 0, y = ax + b is simply y = b. So only A. and B. make sense so far.

When y = 0, y = ax + b is simplifies to 0 = ax + b which simplifies to ax = -b. By plugging x = 22.5, you should be able to deduce which of the answers is right. I can confirm if you'd like
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Circle O has a circumference of approximately 44 in. What is the approximate length of the diameter, d? inches
LenKa [72]
The distance around a rectangle or a square is as you might remember called the perimeter. The distance around a circle on the other hand is called the circumference. It is calculated as follows:

C = 2pi(r)

From this, we can solve for r and evetually solve for the diameter.

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Read more on Brainly - brainly.com/sf/question/2502148
3 0
3 years ago
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The real numbers $x$ and $y$ are such that \begin{align*} x + y &= 4, \\ x^2 + y^2 &= 22, \\ x^4 &= y^4 - 176 \sqrt{
tamaranim1 [39]

You get everything you need from factoring the last expression:

x^4-y^4=-176\sqrt7

The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)

Plug in everything you know and solve for x-y:

-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}

4 0
3 years ago
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What is the area of the trapezoid with height 10 units?
Ainat [17]
Ya but I think its like 40 hope this helps
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Hiii please help i’ll give brainliest if you give a correct answer please thanks!
Archy [21]

Answer:

1. 12

2. the prism with a length of 7  1/2 will have a shorter width, with a width of 6

8 0
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There is $100 it goes up 10% how much is it
Umnica [9.8K]
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