All categories

2 years ago

Dex estimates that 49,892 ÷ 0.89 is about 5,000. Is his estimate reasonable? Why or why not?

Mathematics

2 answers:

pshichka [43]2 years ago

6 0

Answer:

Step-by-step explanation:

Why don’t you have no calculator homie

SVEN [57.7K]2 years ago

3 0

Answer:yes

Step-by-step explanation:

because 0.89 is a very small number so itd be reasonable for it to be a large number

You might be interested in

Badly needed it now.

melamori03 [73]

Answer:

Step-by-step explanation:

1.litres is the variation statement in the problem.

2.initial volume and distance and final distance is given.

3 0

2 years ago

State if these 3 numbers can be the measures of the sides of a triangle.

Feliz [49]

Answer:

they can all be mesures of a triangle

7 0

2 years ago

A line of best fit can only be established for data with positive correlation. true or false

Vanyuwa [196]

I think it would be true

8 0

3 years ago

Read 2 more answers

If an object is dropped from a height of 144 feet, the function h(t)=-16t^2+144 gives the height of the object after t seconds.

shtirl [24]

Answer:

A. 3s

Step-by-step explanation:

The height of the object after t seconds is given by:

$h(t) = -16t^2 + 144$

When will the object hit the ground?

It hits the ground after t seconds, and t is found when $h(t) = 0$ . So

$h(t) = -16t^2 + 144$

$0 = -16t^2 + 144$

$16t^2 = 144$

$t^2 = \frac{144}{16}$

$t^2 = 9$

$t = \sqrt{9}$

$t = 3$

3 seconds, so the correct answer is given by option a.

5 0

2 years ago

An education firm measures the high school dropout rate as the percentage of 16 to 24 year olds who are not enrolled in school a

posledela

Answer:

The value of the test statistic $z = -0.6606$

Step-by-step explanation:

From the question we are told that

The high dropout rate is $\mu = 6.1$ % $= 0.061$

The sample size is $n = 1000$

The number of dropouts $x = 56$

The probability of having a dropout in 1000 people $\= x = \frac{56}{1000} = 0.056$

Now setting up Test Hypothesis

Null $H_o : p = 0.061$

Alternative $H_a : p < 0.061$

The Test statistics is mathematically represented as

$z = \frac{\= x - p}{\sqrt{\frac{p(1 -p)}{n} } }$

substituting values

$z = \frac{0.056 - 0.061}{\sqrt{\frac{0.061(1 -0.061)}{1000} } }$

$z = -0.6606$

6 0

2 years ago