Answer:
midpoint (5,4)
Step-by-step explanation:
The midpoint(M) of a segment with endpoints (x₁ , y₁) and ( x₂, y₂) is
where x₁ = 2 and x₂ = 8
y₁ = 0 and y₂ = 8
M = 
M = 
M = 5 , 4
The answer is 18. Just take the number that comes later and simply subtract from the original number. EXAMPLE- 138-120=18. Hope this helps.
Jacob has 4 balloons, because 4 is half of 8
Hope this helps ya ;)
The speed is:
S = 742.5ft
The distance that the parachutist falls in 5 seconds is:
D = 742.5ft
<h3>
How to get the speed in feet per second?</h3>
We know that the speed in free fall is:
S = 45 m/s.
We know that:
1 m = 3.3ft
Then we can rewrite the speed as:
S = 45 m/s = 45 *(3.28ft)/s = 148.5 ft/s
Then, the distance that the parachutist falls during 5 seconds is:
D = S*5s = (148.5 ft/s)*5s = 742.5ft
If you want to learn more about speed:
brainly.com/question/4931057
#SPJ1
Recall the angle sum identities:


Now,

Divide through numerator and denominator by
to get

Next, we use the fact that
lie in the first quadrant to determine that


So we then have


Finally,
