Aiden has two toy cars that measure two and one fourth inches, three that measure two three eight inches, one that measures two
1 answer:
Answer:
So, the longest toy car length is
Step-by-step explanation:
Given - Aiden has two toy cars that measure two and one fourth inches,
three that measure two three eight inches, one that measures two
and seven eights inches, one that measures 2 and one eights
inches, and one that measures two and three fourths inches.
To find - How long is Aiden's longest toy car.
Proof -
Measure of 1st car - 2 inches
Measure of 2nd car - = 0.25 inches
Measure of 3rd car - = 2.375 inches
Measure of 4th car - = 2.875 inches
Measure of 5th car - = 2.125 inches
Measure of 6th car - = 2.75 inches
So, the longest toy car length is (2.875 inches )
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Answer:
So on this case the 95% confidence interval would be given by (15.641;18.359)
And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm
Step-by-step explanation:
Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean
population mean (variable of interest)
s=1.9 represent the sample standard deviation
n=10 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the critical value we need to find first the degrees of freedom, given by:
Since the Confidence is 0.95 or 95%, the value of and
, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,9)".And we see that
Now we have everything in order to replace into formula (1):
So on this case the 95% confidence interval would be given by (15.641;18.359)
And since the lower limit for the confidence interval is higher than 15 we can conclude that at 5% of significance the true mean is higher than 15 cm