How do I do this :'(

Mathematics

2 answers:

kykrilka [37]3 years ago

7 0

-14sqrt6

break up the radicand into a product of known factors of its self.

Svetllana [295]3 years ago

4 0

294÷ 6 shows that 6(49)= 294. The square root of 49 is 7, so you can remove the 49 from inside the square root and multiply it by the -2 outside the root to get -14. that leave only the 6 inside the square root, so your answer is -14√6

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PLS HURRY I NEED THE ANSWER FAST

balandron [24]

Answer:

notice how a right triangle was formed, and the Pythagorean theorem could be used to solve this :

a^2 + b^2 = c^2

a^2 + 15^2 = 17^2

a^2 + 225 = 289

a^2 = 64

a= 8

multiply it by 2 to get the side of the base

8 * 2 = 16

5 0

3 years ago

The measures of the base angles of an isosceles triangle are 3x 5 and 5x - 25. The measure of the vertex angle is 6x - 10. Find

lukranit [14]

Answer: The measure of the vertex angle = 80°

Step-by-step explanation:

Angle sum property of triangle : The sum of the measures of the angles for any triangle is 180 degrees.

So,

$3x+ 5 + 5x-25+6x-10= 180\\\\\Rightarrow\ 14x-30=180\\\\\Rightarrow\ 14x= 210\\\\\Rightarrow x=\dfrac{210}{14}=15$ '

Then, vertex angle = $6(15)-10=90-10= 80$

Hence, The measure of the vertex angle = 80°

5 0

3 years ago

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .