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2 years ago

11

There is space for 120 students to go on a field trip. Currently, 74 students have signed up. Write and solve an inequality to f

ind how many more students can sign up for the field trip.
Please help

1 answer:

sukhopar [10]2 years ago

5 0

Answer:

46

Step-by-step explanation:

$120 - 74 = 46$

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3 years ago

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2 years ago

Find the sum of the finite geometric series. 4 20 100 ... 312,500 the sum of the geometric series is .

AnnZ [28]

What is the 9th term of the geometric sequence 4, -20, 100, ...
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2 years ago

2. The ratio of radii of two cylinders is 1:2 and heights are in the ratio 2:3. Find the ratio of their volumes.

Savatey [412]

Answer: $\frac{1}{6}$ or $1:6$

Step-by-step explanation:

The volume of a cylinder can be found with the following formula:

$V=\pi r^2h$

Where "r" is the radius and "h" is the height of the cylinder.

In this case, let be:

- $V_1$ the volume of one of this cylinders and $V_2$ the volume of the other one.

- $r_1$ the radius of the first one and $r_2$ the radius of the other cylinder.

- $h_1$ the height of one of them and $h_2$ the height of the other cylinder.

Then:

$V_1=\pi r_1^2h_1\\\\V_2=\pi r_2^2h_2$

Therefore, you know this:

$\frac{V_1}{V_2} =\frac{\pi r_1^2h_1}{\pi r_2^2h_2}$

Simplifying, you get:

$\frac{V_1}{V_2} =\frac{ r_1^2h_1}{ r_2^2h_2}$

Now, knowing the ratios given in the exercise, you can substitute them into the equation:

$\frac{V_1}{V_2} =\frac{1^2*2}{ 2^2*3}$

Evaluating, you get:

$\frac{V_1}{V_2} =\frac{2}{ 4*3}\\\\\frac{V_1}{V_2} =\frac{2}{12}\\\\\frac{V_1}{V_2} =\frac{1}{6}$

4 0

3 years ago

It costs more to produce defective items - since they must be scrapped or reworked - than it does to produce non-defective items

ale4655 [162]

Answer: a) 1082, b) wider.

Step-by-step explanation:

Since we have given that

Margin of error = 0.1 millimeter = E

Standard deviation = 2 mm = σ

Critical value would be

$z_{\frac{\alpha}{2}}=z_{0.05}=1.645$

a) Sample size would be

$n=(\dfrac{z_{\frac{\alpha }{2}}\times \sigma}{E})^2\\\\n=(\dfrac{1.645\times 2}{1})^2\\\\n=1082.41\\\\n=1082$

b) Sample size, n = 100

So, the margin of error would be

$E=z_{\frac{\alpha }{2}}\times \dfrac{\sigma}{\sqrt{n}}\\\\E=1.645\times \dfrac{2}{\sqrt{100}}\\\\E=1.645\times \dfrac{2}{10}\\\\E=0.329$

Since the margin of error in b part is more than a part, as we know that the higher the margin of error, the wider the confidence interval.

So, it would have wider confidence interval.

Hence, a) 1082, b) wider.

4 0

3 years ago