It’s using the distributive method. 7 x a is 7A and 7 x 13 is 91, therefor it is 7A+91.
Answer:
q= -ck+dp/
-k+d
Step-by-step explanation:
Step 1:
Multiply both sides by p.
dp=ck−kq+pq
Step 2:
Flip the equation.
ck−kq+pq=dp
Step 3:
Add -ck to both sides.
−kq+pq=−ck+dp
Step 4:
Factor out variable q.
q(−k+p)=−ck+dp
Step 5:
Divide both sides by -k+p.
q= -ck+dp/
-k+d
Sorry if it's all letters and u needed numbers.
The value of the function f(g) after simplifying and putting 2 in place of <em>x</em> is -20 and the value of f(g(2)) is 418.
<h3>What is composite function?</h3>
When a function is written inside the another function, then such function is called the composite function.
The first function given in the problem is,

The second function given,
To find out the value of g(2), put the 2 on place of variable x in the above equation as,

The composite function f(g(x)) can be given as,

Thus, the value of the function f(g) after simplifying and putting 2 in place of <em>x</em> is -20 and the value of f(g(2)) is 418.
Learn more about the composite function here:
brainly.com/question/10687170
a.
×
A
b.
×
A
c.
A
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
<h3>How to determine the current</h3>
The formula for finding current
I = V/R
Where v = voltage
R = resistance
A. V = 12V
R = 4. 7 + 15 = 19. 7 kΩ = 19700 Ω in series

×
A
B. V = 9V
R = 4. 7 + 1 = 4. 7 kΩ = 4700Ω in series

×
A
C. V= 12V
1/R =
=
× 
R =
= 310. 56 Ω

A
It is important to note that the brightness of a bulb depends on both current and voltage depending on whether the bulb it is in parallel or series.
The LED which would glow brightest is LED C with the greatest current and voltage
The LED which would be the most dim is LED B with low voltage and consequently low current.
Learn more about Ohms law here:
brainly.com/question/14296509
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The length of the base is 24 cubic inches