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3 years ago

I have a bag of m&m's. there are 9 green m&m's and this is 30% of the bag. how many total m&m's are in the bag?

Mathematics

1 answer:

Sergio [31]3 years ago

4 0

Answer:

30 total m&m's

Step-by-step explanation:

You want to find the rest of the bag, which is 70% of the bag (100% - 30%). The question is basically asking: What is 70% of x if 30% of x is equal to 9? The variable x represents the total m&m's in the bag.

Create an equation that models 30% of x.

30%x = 9 ⇒ 0.3x = 9

To solve for x, divide both sides of the equation by 0.3.

x = 30

We know that the value of x is 30, so this means that there is a total of 30 m&m's in the bag. However, to check your answer substitute the value of x into the expression for "What is 70% of x?"

This question can be modeled by: 70%x or 0.7x.

Substitute 30 for x.

0.7(30) = 21

Now take this amount and add this to the known amount of green m&m's in the bag.

21 + 9 = 30

After checking our answer we can verify that 30 is the correct answer.

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Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

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3 years ago

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Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

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Generalising this result

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Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

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