Answer: 278.30 pounds (if the gasoline does not contain ethanol)
317.12 pounds (if the gasoline does contain ethanol)
Step-by-step explanation:
If the truck averages 12 miles per gallon, then in 170 miles it consumes:
170mi/12mi = 14.17 gallons.
We know that for one gallon consumed, the carbon dioxide emitted into the atmosphere is 19.64 pounds. (assuming it does not contain ethanol)
Then for 14.17 gallons consumed, we have a emission of:
14.17*19.64 pounds = 278.30 pounds
I the gasoline contains ethanlol, for a gallon the emiision is around 22.38 pounds.
In this case the total emission is:
14.17*22.38 pounds = 317.12 pounds
Answer:
Answer is B ( 314.9 m2)
Step-by-step explanation:
A= H(B)/2
A= 25.6(24.6)/2
A= 314.88
Answer:
C=5.831
a=30.964
b=59.036
Step-by-step explanation:
Answer:
M = 29
27.31838095 = n
16.8511209 = p
Step-by-step explanation:
M = 180 -33-118 = 29
We can use the rule of sines
sin A sin B sin C
------------ = ---------- = ------------
a b c
sin 118 sin 29
------------ = ----------
n 15
Using cross products
15 sin 118 = n sin 29
Divide by sin 29
15 sin 118 / sin 29 = n
27.31838095 = n
sin 33 sin 29
------------ = ----------
p 15
Using cross products
15 sin 33 = p sin 29
Divide by sin 29
15 sin 33 / sin 29 = p
16.8511209 = p
Answer:
-18
Step-by-step explanation:
-15+6=-9
the absolute value of -9 is 9
and 9*-2=-18
