Question

the area of a rectangular wall of barn is 160 square feet. its length is 4 feet longer than twice its width. find the width of the wall of the barn

Answer 1

Answer:

8 feet

Step-by-step explanation:

Given: the area of a rectangular wall of barn is 160 square feet. its length is 4 feet longer than twice its width.

To Find:  the width of the wall of the barn

Solution:

Area of rectangular wall of barn $=160$ $\text{sq.feet}$

Let the length of wall of barn is $=\text{l}$

Let the width of wall of barn is $=\text{b}$

now,

length of wall of barn is, $\text{l}=2\text{b}+4$

Area of wall of barn $=\text{length}\times\text{width}$

                                 $=\text{l}\times\text{b}$

                                 $(2\text{b}+4)\text{b}$

           $(2\text{b}+4)\text{b}=160$

           $2\text{b}^2+4\text{b}=160$

           $\text{b}^2+2\text{b}=80$

           $\text{b}^2+2\text{b}-80=0$

on factorizing

            $(\text{b}+10)(\text{b}-8)=0$

 as width cannot be less than zero,

            $\text{b}=8$ $\text{feet}$

Width of the wall of barn is   $8$ $\text{feet}$

Answer 2

The solution for finding the width of the wall of the barn is as follows:

W + 4 equals length. 

Multiply width time length to equal 160. 

W(w+4) = 160

w(squared) + 4w equals 160. 

W = 10.80 ft

Therefore, the width of the wall of the barn is 10.80 ft

I hope that helps you.