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3 years ago

1.3(8-b)+3.7b= -5.2 solve and check answer

Mathematics

2 answers:

Paraphin [41]3 years ago

6 0

Answer:

b = -6.5

Step-by-step explanation:

I am 100% sure thts the right answer

Dafna1 [17]3 years ago

3 0

Answer:

b=-6.5 is your answer.

Step-by-step explanation:

What you have to do is get b by itself.

1.3(8-b)+3.7b=-5.2

10.4-1.3b+3.7b=-5.2

2.4b+10.4=-5.2

2.4b=-15.6

b=-6.5 is your answer.

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Butoxors [25]

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3 years ago

I need help!! This is getting a little harder than I expected

MAXImum [283]

Length of the side = 9 cm

Diagonal = $9\sqrt{2}$ cm

Solution:

Area of the square = 81 square centimeters

In square all sides are equal.

Area of the square = side × side

Side × side = 81

Side² = 9² (∵81 = 9²)

Taking square root on both sides, we get

Side = 9 cm

Length of the side = 9 cm

To find the length of the diagonal:

In square all the angles are right angle.

Diagonal splits the square into two right angle triangle.

Using Pythagoras theorem,

In right triangle, square of the hypotenuse is equal to the sum of the square of the other two sides.

Here, diagonal is the hypotenuse.

$\text{Diagonal}^2=9^2+9^2$

$\text{Diagonal}^2=81+81$

$\text{Diagonal}^2=2\times 81$

Taking square root on both side,

Diagonal = $9\sqrt{2}$ cm

6 0

3 years ago

What is the degree of the function f(x)=x⁴-5x+8+x²?

DENIUS [597]

First put it in decreasing power according to x.

x^4-5x+8+x^2

=x^4+x^2-5x+8

Now this question is asking what is the highest degree of x you see in this function.

4 of course.

Therefore the answer to his question is degree of 4.

Done!

7 0

3 years ago

The volume, V, of a right cone varies jointly with the square of the radius of the base, r, and the height, h. When r = 6 and h

Sveta_85 [38]

Answer:

V=πr^2(h/3)

Step-by-step explanation:

V=π6^2(8/3)

6 0

3 years ago

What is an equation of the line that passes through the point (-7, -6) and is parallel to the line x-y=7?

Alex_Xolod [135]

Answer:

Step-by-step explanation:

For two lines to be parallel their slopes must be equal. For two lines to be perpendicular their slopes must be the negative reciprocal of each other.

Step 1 Find the slope of the equation.

Put it into the slope-intercept form. y = mx + b.

For x-y = 7, move the x to the left; therefore subtract the x from both sides. this leaves you -y = -x + 7

Then, divide both sides by -1 to get a positive y. -y/-1 = (-x + 7)/-1

This leaves y = x - 7 The slope(m) for this equation is m = 1

The other equation must also have a slope of 1 or m=1 for the lines to be parallel.

Use the point given to you (-7, -6) and substitute for (x, y)

The slope-intercept form y = mx + b can once again be used.

x = -7, y =-6, and slope or m = 1

Therefore, y = mx + b substituted will be -6 = (1)(-7) + b; now, solve for b which is the y intercept

-6 = -7 + b add 7 to both sides -6 +7 = -7 + b +7 ; therefore, b = 1

Now you know the slope(m) which is equal to 1 and the y-intercept(b) which is equal to 1.

Finally, substitute the m and b in the slope-intercept form

y = (1)x + 1 or y = x +1

5 0

2 years ago