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tensa zangetsu [6.8K]

3 years ago

14

Four numbers from the set 0 to 9, including 0 and 9, are used to create a personal identification number. Once a number is used,

it cannot be reused. How many possible outcomes exist for the situation? How many possible outcomes begin with a 0? What is the theoretical probability of choosing a personal identification number that begins with a 0?

2 answers:

Neporo4naja [7]3 years ago

8 0

Answer:

Four numbers from the set 0 to 9, including 0 and 9, are used to create a personal identification number. Once a number is used, it cannot be reused.

How many possible outcomes exist for the situation? 5040

How many possible outcomes begin with a 0? 504

What is the theoretical probability of choosing a personal identification number that begins with a 0? .1

Hope this helps! Brainliest plz

Novay_Z [31]3 years ago

5 0

Possible outcomes: 5040
Possible to begin with a 0: 504
Theoretical probability: 0.1

These are the correct answers

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Modeling Radioactive Decay In Exercise, complete the table for each radioactive isotope.

Travka [436]

Answer :

The amount after 1000 years will be, 5.19 grams.

The amount after 10000 years will be, 0.105 grams.

Step-by-step explanation :

Half-life = 1599 years

First we have to calculate the rate constant, we use the formula :

$k=\frac{0.693}{t_{1/2}}$

$k=\frac{0.693}{1599\text{ years}}$

$k=4.33\times 10^{-4}\text{ years}^{-1}$

Now we have to calculate the amount after 1000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 1000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$1000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=5.19g$

Thus, the amount after 1000 years will be, 5.19 grams.

Now we have to calculate the amount after 10000 years.

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $4.33\times 10^{-4}\text{ years}^{-1}$

t = time passed by the sample = 10000 years

a = initial amount of the reactant = 8 g

a - x = amount left after decay process = ?

Now put all the given values in above equation, we get

$10000=\frac{2.303}{4.33\times 10^{-4}}\log\frac{8}{a-x}$

$a-x=0.105g$

Thus, the amount after 10000 years will be, 0.105 grams.

4 0

3 years ago

Help with math algebra question in the picture

VashaNatasha [74]

Answer:

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3 years ago

Let a, b, c, and d be real numbers with a, c 6= 0. Prove that the lines y = ax+b and y = cx + d have the same x-intercept if and

Monica [59]

Step-by-step explanation:

We have got the lines :

$y=ax+b\\y=cx+d$

Both lines intercept the x-axis in the point :

$I = (i_{1} ,i_{2})$

In all point from x-axis the y-component is equal to 0.

$I=(i_{1},o)$

We replace the I point in the lines equations:

$0=a(i_{1})+b \\0=c(i_{1})+d$

From the first equation :

$0=a(i_{1})+b \\-b=a(i_{1})\\i_{1}=\frac{-b}{a}$

From the second equation :

$0=c(i_{1})+d\\ -d=c(i_{1})\\i_{1}=\frac{-d}{c}$

Then $i_{1}=i_{1}$

Finally :

$\frac{-b}{a}=\frac{-d}{c} \\\frac{b}{a}=\frac{d}{c} \\ad=bc$

y = ax + b and y = cx + d have the same x-intercept ⇔ad=bc

8 0

3 years ago

Slope intercept! Please help! Will mark brainliest.

avanturin [10]

3) y = $-\frac{1}{2}$ x + 3

Slope-intercept form is y = mx + b when m is the slope and b is the y-intercept

b = 2 (line hits y-axis at 2)

m = $\frac{rise}{run} or\frac{change.in.y}{change.in.x}$ so $\frac{1}{2}$ and the line is negative, so $-\frac{1}{2}$

Write our equation by putting the parts together, and we get:

y = $-\frac{1}{2}$ x + 3

4) y = $-\frac{2}{3}$ x - 1.67

Point slope form is y - y1 = m (x - x1) when y1 is the y coordinate of the point, m is the slope, and x1 is the x coordinate of the point

y - y1 = m (x - x1)

Finding the slope (same as above) results in $-\frac{2}{3}$

<em>*aaaa I have to go, good luck, I do have the answer just no times to write out the steps, good luck and have a nice day!*</em>

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3 years ago

Lucy’s rectangular garden is 15ft long and 12 ft wide. She adds a right triangle to her garden plan, so that the triangle’s heig

KIM [24]

Okay, so lets break this down.

First of all, we have the rectangular garden with a length of 15ft and a width of 12feet. We need to find the area of this which is pretty simple. This would be 15ft times 12ft which is 180ft².

Okay, now time for the triangle. The way that it words it may be confusing but I can draw you a picture of what it looks like (its a quick draw so it looks kinda bad).

But, for the triangle we are going to extend the 12ft line (shorter side; width) and create a line that is 7 feet long. Then, we are going to find the midpoint of the 15ft side and connect that with the end point of the triangle.

Since its on the longer side and its the midpoint, the triangle is going to have a base of 7.5ft (half of 15). Then, the height is 7ft as included in the question.

Now to solve the area of a right triangle, you can use 1/2(bh). So 1/2 of the base times height.

This is 1/2 of (7.5*7) which is 1/2(52.5) and finally the area of the triangle is 26.25ft².

Now, all you gotta do is add the 26.25ft² and the 180ft² together and you get 206.25ft²

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2 years ago