Can you think of another combination of triangle classification that is impossible?

Mathematics

1 answer:

cestrela7 [59]3 years ago

3 0

How about an equilateral right triangle or equiangular right triangle hope this helps

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2. A canoe travels 3 kilometers in

Dmitry_Shevchenko [17]

The average speed of the canoe is 5 1/4 in kilometers per hour

8 0

2 years ago

For circle O, mCD=125° and m

Burka [1]

CA is a diameter of the circle, so $m\widehat{AC}=180^\circ$ , which means $m\angle AOB=m\angle AOD=m\widehat{AD}=180^\circ-m\widehat{CD}=55^\circ$ . Then $m\boxed{\angle ABO}=90^\circ-55^\circ=35^\circ$ .

This means $m\angle CBO=55^\circ-35^\circ=20^\circ$ . Also, if $m\angle AOB=55^\circ$ , then $m\angle BOC=180^\circ-55^\circ=125^\circ$ , which in turns tells us that $m\boxed{\angle BCO}=180^\circ-20^\circ-125^\circ=35^\circ$ .