Can you think of another combination of triangle classification that is impossible?
1 answer:
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Answer: See below
Step-by-step explanation:
The transformation from triangle LMN to triangle L'M'N' is the reflection about the line y =x.
The line segment from L to y=x and the line segment from L' to line y=x are congruent.
Yes, we will get the same characteristic if we draw a line from point M to y=x and the line from M' to y=x.
It is because points P', M' and N' are reflections of points P, M, and N respectively about the line y=x.
Graph 1 (attached as first picture)
Graphing a triangle LMN and reflecting it over the line y = x to create triangle L'M'N, we have:
The transformation from triangle LMN to triangle L'M'N' is the reflection about the line y =x.
Drawing a line from point L to the line y=x and from line L' to line y=x we have:
Graph 2 (attached as second picture)
The line segment from L to y=x and the line segment from L' to line y=x are congruent.
Yes, we will get the same characteristic if we draw a line from point M to y=x and the line from M' to y=x.
It is because points P', M' and N' are reflections of points P, M, and N respectively about the line y=x.
