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vivado [14]
3 years ago
15

If you observe a population and find that 16% show the recessive trait, you know the frequency of the aa genotype. this means yo

u know q2. what is the frequency of the homozygous dominant genotype in the population above?
Biology
1 answer:
Schach [20]3 years ago
7 0
If the population is at Hardy-Weinberg equilibrium, then the frequency of the recessive genes would be:
aa=0.16
a= √0.16= 0.4

Then, the frequency of dominant genes would be:
0.4+q=1
q= 1-0.4= 0.6

The frequency of <span>homozygous dominant genotype</span> would be:
qq= 0.6*0.6=0.36= 36%
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