3 log 2x = 4
==> log 2x = 4/3
==> 2x = 10^(4/3)
==> x = \frac{10^(4/3)}{2}
DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
A=11.55in²<span><span><span>lLengthin</span><span>wWidthin</span></span></span>
Answer:
C = (A*P - 8.4Y -330T + 200I) / 100
Step-by-step explanation:
P = (8.4Y + 330T + 100C -200I ) / A
now we have to calculate completed passes C for given P, Y, T, I, A
A*P = 8.4Y + 330T -200I +100C
100C = A*P - 8.4Y - 330T + 200I
C = (A*P - 8.4Y -330T + 200I) / 100
I just solved the equation for C
Let x represent the number of hours he worked during the weekdays (not Saturday or Sunday).
If x is how much he worked on the weekdays and he worked 5 times as much on Sat and Sun, then hopefully you agree that on Sat and Sun he worked 5x hours.
So we have 5x hours on the weekends and x hours on the weekdays, so in total for the whole week we have 5x + x = 6x hours in total.
The question tells us that he worked 30 hours total, so 6x = 30
Divide both sides by 6 to isolate x and we have x = 5.
He worked 5 hours the rest of the week.
Hope this helps. If it does, please be sure to make this the brainliest answer! :)
