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NeX [460]
3 years ago
6

PLEASE HELP!!!!!!!!!!!!!! I’ll give you brainiest!! Do it like Example: 1,2,3

Mathematics
1 answer:
AlexFokin [52]3 years ago
6 0
A) d= [0,9]
b) r= [0, 125]
hope this helps!
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if a committee of 4 is to be chosen at random from the class of 11 students what is the probability of any particular commuter b
Darina [25.2K]

i think the answer is 4/11 because the 4 people has a 1%  chance out of the 11 people

7 0
3 years ago
What is the range of the function graphed below?
Nadusha1986 [10]
Its the second option!

The range expresses the constraints of y-values of a function. There is a solid point at positive three which means that it is included. The open point at -3 means it’s not included. This makes the range -3
3 0
1 year ago
What is 328.618 round to the nearest hundredth<br><br>A. 300<br>B. 328.60<br>C. 330<br>D. 328.62​
son4ous [18]

Answer:

D. 328.62​

Step-by-step explanation:

328.618 round to the nearest hundredth

Rounding to the nearest hundredth means 2 numbers after the decimal point

Numbers that rounds to 1 are 5, 6, 7, 8, 9

Number that rounds to 0 are 0, 1, 2, 3, 4

When rounding up, to the nearest hundredth, you will consider the next number after the two figures after the decimal point

Here, the next number after the two figures after the decimal point is 8

8 is a number that rounds to 1

Therefore, add 1 to 1 to have

328.62​

4 0
2 years ago
Find x and y using subsitution<br><br> -3x + y = 6<br> 5x + 2y =23
vazorg [7]

\left\{\begin{array}{ccc}-3x+y=6&|\text{add 3x to both sides}\\5x+2y=23\end{array}\right\\\\\left\{\begin{array}{ccc}y=3x+6\\5x+2y=23\end{array}\right\\\\\text{substitute}\ y=3x+6\ \text{to the second equation}\\\\5x+2(3x+6)=23\qquad|\text{use distributive property}\\\\5x+(2)(3x)+(2)(6)=23\\\\5x+6x+12=23\qquad|\text{subtract 12 from both sides}\\\\11x=11\qquad|\text{divide both sides by 11}\\\\\boxed{x=1}\\\\\text{subtract the value of x to the first equation}\\\\y=3(1)+6\\\\y=3+6\\\\\boxed{y=9}

<h3>Answer: x = 1 and y = 9 → (1, 9).</h3>
4 0
3 years ago
Read 2 more answers
5 numbers : <br> mode = n median= n+1 mean = n+2 Range = n+3<br><br> find 2 sets of numbers
valentina_108 [34]

Answer:

3,3,4,6,6

4,4,5,6,7

5,5,6,6,8

Step-by-step explanation:

mode = n

median= n+1

mean = n+2

Range = n+3

let sets:

a,b,c,d,e

mode = n, at least two of them are the same and equal to n

n,n,c,d,e

median belong to the set, in ascending order:

n,n,n+1,d,e

which means d,e ≥ n+1, d≠e

mean is n+2

5(n+2)=n+n+n+1+d+e

2n+9=d+e

Assume e is the maximum:

Range is n+3:

e-n=n+3

e=2n+3

d=6≥n+1

n≤5,

Set is n,n,n+1,6,n+3

n+1≤6≤n+3

3≤n≤5

3,3,4,6,6 bimodal

4,4,5,6,7

5,5,6,6,8 bimodal

5 0
3 years ago
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