Observe the sequences below. I. 3, 6, 9, 12, ... II. 3, 9, 27, 81, III. 2, 4, 8, 16, ... IV. 3, 5, 7, 9, Which of these are geom
Sholpan [36]
Observe the sequences below. I. 3, 6, 9, 12, ... II. 3, 9, 27, 81, III. 2, 4, 8, 16, ... IV. 3, 5, 7, 9, Which of these are geometric sequences? III only O Il and me II and IV O I and
Answer:
I think the answer is false but im not sure
Step-by-step explanation:
i hope this helps
In the slope intercept form equation of a line (y=ax+b) a represents the slope, and b represents the intercept, which is -5. Thus, we know y=ax-5. The slope can be found by creating a fraction with the change in y value on top, and the change of x value on the bottom. If we have two points (4, 1) and (0, -5) we can put this into a fraction -
, which simplifies down to -6/-4, or 3/2. Thus the answer is f(x)=
x-5<span />
Answer:
18. Sqrt40 goes between 6 and 7.
19. Sqrt83 ~= 9
Step-by-step explanation:
For both of these problems, it's really useful to be very familiar with the perfect squares on the times table. 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225...
On #18, we're looking at the sqrt40. This will be between sqrt36 and sqrt49, because 40 is between 36 and 49. But sqrt36 is 6 and sqrt49 is 7. So sqrt40 is between 6 and 7.
For #19, the sqrt83 is far closer to sqrt81 than it is to sqrt100. Sqrt81 = 9. So sqrt83 is very close to 9, it would round to 9 and not 10.
id a is d than c is b butvthey arent equal so the answe is a
