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Anna71 [15]
3 years ago
5

Can some one help me with this I got the answer but not sure I've the steps?

Mathematics
1 answer:
frez [133]3 years ago
8 0
I belive what you did wrong is that you didint show your work so what you have to do is explain how to do the problem with equations or explain in word form if i were you i would show my work in equations if you need help on how to set it up contact me.
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3 Simple Questions! Help! 99 Points! Brainliest!
WARRIOR [948]

Answer:

1.       ridescost+admission=total

if x=number of tickets and y is total and cost per ride is 1.25 then

1.25x+admission=y

if we solve

when x=25, y=43.75

1.25(25)+admission=43.75

31.25+admission=43.75

minus 31.25 from both sides

admission=12.50

a.

y=1.25x+12.5

b.

x is number of tickets and y is total cost

c. math, seriously, just read what is above option a (the one in the top of the answer)

if you're too lazy then:

ridescost+admission=total

if x=number of tickets and y is total and cost per ride is 1.25 then

1.25x+admission=y

if we solve

when x=25, y=43.75


2.    

(a)  

m = (y2 - y1) / (x2 - x1) = (4 - 9)/(-2 - 8) = -5/(-10) = 1/2  

(b)  

y - y1 = m(x - x1)  

Using the first given point,  

y - 9 = (1/2)(x - 8)  

Using the second given point,

y - 4 = (1/2)(x + 2)

note they both simplify to  

y = (1/2)x + 5  

(c)  

y = (1/2)x + 5


3.        

5 0
3 years ago
Points P(5, 7) and Q(-1, 1) lie on the graph of y = x + 2.
Arisa [49]

Answer:

R is not collinear.

S is collinear.

Step-by-step explanation:

The equation of the graph is given by y =x +2 ........ (1).

Now, the points P and Q having coordinates (5,7) and (-1,1) respectively lie on the graph of the equation (1) because those points satisfy the equation.

Now, if we consider another point R having coordinates (1,-1), then it does not lie on the graph of equation (1) as it does not satisfy the equation.{If you put x=1, then y will be 3 but not -1}

Therefore, P, Q, R are not collinear. (Answer)

Again if we consider the point S(-3,-1), it satisfies equation (1).{If you put x=-3 in the equation (1), y will be -1}.

Therefore, P, Q, and S lie on the same straight line. and they are collinear. (Answer)

6 0
3 years ago
Find UX and the area of △UVW.
Mkey [24]

Answer:

UX ≈ 4.5

△UVW = 49.5 ft²

Step-by-step explanation:

[] We can assume that UX is the midline of this triangle.

22 ft / 2 = 11 ft

XW and VX = 11 ft

[] Now that we have 2 sides of a right traingle, we can find the third.

a² + 11² = 12²

a² + 121 = 144

a² = 20

a = about 4.5, which is side UX

[] Since we have all three sides of the triangle, we can also solve for the total triangle's area. To solve for the area of a triangle, we do base times height divided by 2

22 * 4.5 = 99

99 / 2 = 49.5 ft²

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

7 0
3 years ago
The product of seven non-zero factors. of which only three are positive. is
Mekhanik [1.2K]

Answer:

The answer is A

Step-by-step explanation:

This is one of those sneaky questions where you think there is no definite answer, but don't despair. There is an answer.

You have 7 numbers

3 of them are positive which means greater than 0. Let's pick them

3 4 5 = 60

That part's easy. Those 3 numbers give a plus result.

Now try the other 4 numbers

-3  - 2  - 1 - 4

Do you see what's going to happen. You have -3 * - 2 = 6

then you get - 1 * - 4 = 4

All of a sudden you get a positive result 6 * 4 = 24

60 * 24 = 1440

So the answer is any 3 plus numbers multiplied by 4 minus numbers gives a plus result.

4 0
2 years ago
Read 2 more answers
What is the solution set of the equation<br> 3X=-6/1-X<br> for x # 1?
Irina-Kira [14]

The solution set of the equation 3X=-6/1-X for x # 1 is {-2,1)

3x = -6/(1-x)

3x(1-x) = -6

3x – 3x2 = -6

Taking 3 as common from both sides

x –x2 = -2

x2 – x +2 =0

Using factorisation method we will get two factors

Factoring quadratics is a method of expressing the quadratic equation ax2 + bx + c = 0 as a product of its linear factors as (x - k)(x - h), where h, k are the roots of the quadratic equation ax2 + bx + c = 0. This method is also is called the method of factorization of quadratic equations. Factorization of quadratic equations can be done using different methods such as splitting the middle term, using the quadratic formula, completing the squares, etc.

( x – 2)(x+1)=0

So, x = 2 , -1

Now, when x ≠ 1

The solution of the equation will vary from {-2,1) .

Learn more about the factorisation here brainly.com/question/13496719

#SPJ9

3 0
2 years ago
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