Divide (3x^3+5x) by (x+3)
1 answer:
Using synthetic division: Draw an upside down division symbol. Place the constant of x + 3 (-3) on the outside, and the coefficients of 3x³ + 5x on the inside, like so: | x³ x² x¹ x⁰ -3 | 3 0 5 0 | |___________ Bring down the first coefficient: | x³ x² x¹ x⁰ -3 | 3 0 5 0 | |___________ 3 Multiply the number outside the symbol (-3) by the 3 you've just brought down. Place that number under the next coefficient to the right. | x³ x² x¹ x⁰ -3 | 3 0 5 0 | -9 |___________ 3 Add the new number (-9) to the coefficient above it and place that number directly underneath it. | x³ x² x¹ x⁰ -3 | 3 0 5 0 | -9 |___________ 3 -9 Repeat this process until you've reach the end of the symbol. | x³ x² x¹ x⁰ -3 | 3 0 5 0 | -9 27 -96 |___________ 3 -9 32 -96 The resulting numbers are coefficients, the first three of the quotient, and the last one of the remainder. The remainder is the last coefficient (-96) over the divisor. <span>(3x^3+5x) / (x+3) = 3 </span>² - 9x + 32 + -96 / x + 3
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