Answer:
A. Encuentre el
valor absoluto. por definición, el valor absoluto es la magnitud de un número real sin tener en cuenta su signo 1. | 120 | = 120 2. | -45 | = 45 3.
Step-by-step explanation:
Let the first number be 'x' and the second number is 'y'
Equation 1: x + y = 52
Equation 2: x - y = 38
Rearranging equation 2 to make either x or y the subject
x = 38 + y
Substituting x = 38 + y into equation 1
x + y = 52
(38+y) + y = 52
38 + 2y = 52
2y = 52 - 38
2y = 14
y = 7
Substitute y = 7 into either equation 1 or equation 2 to find x
x + y = 52
x + 7 = 52
x = 52 - 7
x = 45
x = 45
y = 7
Answer:
A
Step-by-step explanation:
We are given:

Since cosine is the ratio of the adjacent side over the hypotenuse, this means that the opposite side is (we can ignore negatives for now):

So, the opposite side is 5, the adjacent side is 12, and the hypotenuse is 13.
And since θ is in QIII, sine/cosecant is negative, cosine/secant is negative, and tangent/cotangent is positive.
Cosecant is given by the hypotenuse over the opposite side. Thus:

Since θ is in QIII, cosecant must be negative:

Our answer is A.
Answer:
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Step-by-step explanation:
Given that:
Mean = μ = 150
SD = σ = 12
Let x1 be the first data point and x2 the second data point
We have to find the z-scores for both data points
x1 = 135
x2 = 167
So,

And

We have to find area to the left of both points then their difference to find the probability.
So,
Area to the left of z1 = 0.1056
Area to the left of z2 = 0.9207
Probability to score between 135 and 167 = z2-z1 = 0.9027-0.1056 = 0.8151
Hence,
The probability of his score being between 135 and 167 is 0.8151 or (0.8151*100=81.51%)
Its an Integer. Integers include negative numbers, zero and positive numbers :)