If f = {(4, 2), (6, 1), (8, 4), (10, 2), (12, 5)}, what is the range?

1 answer:

3 0

Given the function:
<span>f = {(4, 2), (6, 1), (8, 4), (10, 2), (12, 5)}
the range is all the y-values, it's not to be confuse with the domain which is all the x-values, thus the range of our function will therefore be the following set.
{2,1,4,2,5}
Answer:
</span>{2,1,4,2,5}

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A swimming pool is being drained so it can be cleaned. The amount of water in the pool is changing according to the función f(t)

TiliK225 [7]

Answer:

0 ≤ t ≤ 5.

Step-by-step explanation:

In the function $f(t)$ , $t$ is the independent variable. The domain of $f$ is the set of all values of $t$ that this function can accept.

In this case, $f(t)$ is defined in a real-life context. Hence, consider the real-life constraints on the two variables. Both time and volume should be non-negative. In other words,

$t \ge 0$ .
$f(t) \ge 0$ .

The first condition is an inequality about $t$ , which is indeed the independent variable.

However, the second condition is about $f$ , the dependent variable of this function. It has to be rewritten as a condition about $t$ .

$\begin{aligned} f(t) &\ge 0 &&\text{Assumption} \cr 80000 - 16000\, t& \ge 0 && \text{Definition of} ~ f \cr 80000 & \ge 16000\, t && \begin{aligned}&\text{Add $16000\, t$} \\[-0.5em] & \text{to both sides of the inequality}\end{aligned} \cr 5 &\ge t &&\begin{aligned}&\text{Divide both sides of} \\[-0.5em] & \text{the inequality by $16000$}\end{aligned} \cr t &\le 5 && \text{Flip the inequality}\end{aligned}$ .