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3 years ago

Let i be the first of four consecutive integers. what is 3 less than the sum of those integers ?

1 answer:

5 0

The consecutive integers are i, i+1, i+2, i+3.

3 less than sum of the integers

= i + i +1 + i + 2 + i + 3 - 3 = 4i + 3

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Two competing headache remedies claim to give fast-acting relief. An experiment was performed to compare the mean lengths of tim

DaniilM [7]

Answer:

$t = 0.875$

Step-by-step explanation:

Given

<u>Brand A</u> <u>Brand B</u>

$n_ 1= 12$ $n_2 = 12$

$\bar x_1 = 21.8$ $\bar x_2 = 18.9$

$\sigma_1 = 8.7$ $\sigma_2 = 7.5$

Required

Determine the test statistic (t)

This is calculated as:

$t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}$

Calculate s using:

$s = \sqrt{\frac{(n_1-1)*\sigma_1^2+(n_2-1)*\sigma_2^2}{n_1+n_2-2}}$

The equation becomes:

$s = \sqrt{\frac{(12-1)*8.7^2+(12-1)*7.5^2}{12+12-2}}$

$s = \sqrt{\frac{1451.34}{22}}$

$s = \sqrt{65.97}$

$s = 8.12$

So:

$t = \frac{\bar x_1 - \bar x_2}{s\sqrt{\frac{1}{n_1} + \frac{1}{n_2}}}$

$t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{12} + \frac{1}{12}}}$

$t = \frac{21.8 - 18.9}{8.12 * \sqrt{\frac{1}{6}}}$

$t = \frac{21.8 - 18.9}{8.12 * 0.408}}$

$t = \frac{2.9}{3.31296}}$

$t = 0.875$

3 0

3 years ago

Which two numbers on the number line have an absolute value of 1.75? Select the location of both numbers on the number line

hram777 [196]

Solution

To find Which two numbers on the number line have sn

absolute value of 1.75 .

Absolute value means " how far a number is from

zero " .

"1.75" is 1.75 away from zero .

and " -1.75" is also 1.75 away from zero .

i.e

| 0 - 1.75 | = 1.75

| 1.75 - 0 | = 1.75

So , the absolute value of "1.75" is 1.75

similarly , absolute value of "1.75" is 1.75 .

Hence , the two numbers are -1.75 and 1.75 .

8 0

2 years ago

Read 2 more answers

Find the product. (-2x^2 )^3 ·3 x

jeka94

Assignment: $\bold{Solve \ \left(-2x^2\right)^3\cdot \:3x}$

<><><><><>

Answer: $\boxed{\bold{-24x^7}}$

<><><><><>

Explanation: $\downarrow\downarrow\downarrow$

<><><><><>

[ Step One ] Rewrite $\bold{\left(-2x^2\right)^3}$

$\bold{-2^3\left(x^2\right)^3}$

[ Step Two ] Rewrite Equation

$\bold{-2^3\cdot \:3x^6x}$

[ Step Three ] Apply Exponent Rule

Note: $\bold{Exponent \ Rule \ \:a^b\cdot \:a^c=a^{b+c}: \ x^6x=\:x^{6+1}=\:x^7}$

$\bold{-2^3\cdot \:3x^7}$

[ Step Four ] Refine

$\bold{-24x^7}$

<><><><><><><>

$\bold{\rightarrow Rhythm \ Bot \leftarrow}$

4 0

3 years ago

Read 2 more answers

The difference of the square of a number and 4 is equal to 3 times that number. Find the positive solution.

liberstina [14]

Let the number be 'a':

The difference of the square of a number and 4

a^2 -4

is equal to 3 times that number.

= 3*a

a^2 -4 =3a

a^2 -3a -4=0

(a-4) (a+1)=0

solutions are: 4 and -1

8 0

2 years ago

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Enter <,>,= to make the problem true -19 5/6 _ -20 1/6

NemiM [27]

Answer:

..................................................................

8 0

2 years ago