3 years ago

Verbal expression for seven to the 3rd power

1 answer:

4 0

7^3 power is the answer to your question

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Nitella [24]

Answer:

$W=2452.5 J$

Step-by-step explanation:

The work is define as the integral of the force times distance. So we have:

$W=\int^{a}_{b}Fxdx$

Now, we can write the force in terms of density.

$F=m*g=\rho Vg$

V is the volume (V=2*1*1=2 m³)

So the work will be:

$W=\int^{0.5}_{0} 2*1000*9.81*xdx=\int^{0.5}_{0} 2*1000*9.81*xdx=\int^{0.5}_{0}19620xdx=19620(\frac{x^{2}}{2})|^{0.5}_{0}$

The limit of integration is between 0 and 0.5 because we want to pump half of the water out of the aquarium.

$W=19620(\frac{x^{2}}{2})|^{0.5}_{0}=19620(\frac{0.5^{2}}{2})$

$W=2452.5 J$

I hope it helps you!

8 0

3 years ago

maksim [4K]

All given options are incorrect .. As no one is the equation of a circle

6 0

3 years ago

Licemer1 [7]

Answer:

figure 3

Step-by-step explanation:

8 0

3 years ago

Allushta [10]

Your answer is.............B. Negative.

3 0

3 years ago

photoshop1234 [79]

ok but what's the question? u gave us info but what's the question

8 0

2 years ago