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jekas [21]
3 years ago
6

Help pleaseeeeeeeeee

Mathematics
1 answer:
vazorg [7]3 years ago
7 0

Answer:

3/-2

Step-by-step explanation:

All I did was put - 3/2 into my calculator and got the answer. I than found the answer for the rest of the fractions and only the first one equals to - 3/2.

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Offering tons of points and brainliest for the right answer!
poizon [28]

Answer:

6

Step-by-step explanation:

I'm so sorry if it's incorrect

5 0
2 years ago
The sum of three consecutive integers is -51 what is the value of the smallest number
zubka84 [21]

Answer: Let's say the first number is x, the next one is x+1, and so on

Step-by-step explanation:

x + (x + 1) + (x + 2) = -51

x + x + 1 + x + 2 = -51

3x + 3 = -51

3x = -54

x = -18

8 0
3 years ago
PLEASE HELP WILL MARK BRAINLIEST!!!
Gala2k [10]

     The Unit Rate is the start of the slope/the y-intercept of the slope.To find that we need to make the slope first.

(shown in the first picture)

      We can see that the slope is a linear function/a straight line, and if we just follow the line down the slope we can see that it has a y-intercept/unit rate of 2/3 of 1 whole.

(the second picture)

6 0
2 years ago
Let g(x)=Intragal from 0 to x f(t) dt, where r is the function whos graph is shown.
leonid [27]

If

\displaystyle g(x) = \int_0^x f(t) \, dt

then g(x) gives the signed area under f(x) over a given interval starting at 0.

In particular,

\displaystyle g(0) = \int_0^0 f(t) \, dt = 0

since the integral of any function over a single point is zero;

\displaystyle g(4) = \int_0^4 f(t) \, dt = 8

since the area under f(x) over the interval [0, 4] is a right triangle with length and height 4, hence area 1/2 • 4 • 4 = 8;

\displaystyle g(8) = \int_0^8 f(t) \, dt = 0

since the area over [4, 8] is the same as the area over [0, 4], but on the opposite side of the t-axis;

\displaystyle g(12) = \int_0^{12} f(t) \, dt = -8

since the area over [8, 12] is the same as over [4, 8], but doesn't get canceled;

\displaystyle g(16) = \int_0^{16} f(t) \, dt = 0

since the area over [12, 16] is the same as over [0, 4], and all together these four triangle areas cancel to zero;

\displaystyle g(20) = \int_0^{20} f(t) \, dt = 24

since the area over [16, 20] is a trapezoid with "bases" 4 and 8, and "height" 4, hence area (4 + 8)/2 • 4 = 24;

\displaystyle g(24) = \int_0^{24} f(t) \, dt = 64

since the area over [20, 24] is yet another trapezoid, but with bases 8 and 12, and height 4, hence area (8 + 12)/2 • 4 = 40, which we add to the previous area.

5 0
3 years ago
What is the equation of the blue graph?
Tanya [424]
G(x) = (x-2)^3
move F(x) = x^2 to the right 2 units

answer
C. G(x) = (x-2)^3
6 0
3 years ago
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