The answer would be 16 S'mores and the limiting reactant would be the grahams.
(This is assuming that S'mores would need 2 grahams, 1 marshmallow and 1 chocolate piece.)
Limiting reactant would be the reactant that runs out first.
Let's take your problem into account and see what we have:
48 marshallows
32 grahams (2 x 16 per pack)
45 chocolate pieces (5 x 15 pieces per bar)
Since need 2 of the grahams per S'more then the maximum yield of the grahams is 16 S'mores.
The maximum yield of marshmallows is 48.
The maximum yield of chocolate is 45.
Since you cannot make S'mores without the grahams, then you can only make 16 S'mores before the grahams run out.
<h3>
Answer: f( h(x) ) = 2x - 4</h3>
Work Shown:
f(x) = x - 7
f( h(x) ) = h(x) - 7
f( h(x) ) = 2x+3 - 7
f( h(x) ) = 2x - 4
Explanation:
In the second step, I replaced every x with h(x). In the next step, I replaced the h(x) on the right hand side with 2x+3. From there I combined like terms.
4(4x + 5)
4(4•7+5)
4(28+5)
4(33)
132
Answer:
the answer is 96
Step-by-step explanation:
hope this helps :)
