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FrozenT [24]
3 years ago
14

What is 17over 40 as a decimal

Mathematics
2 answers:
Lerok [7]3 years ago
7 0

2.6 I think that's the answer to it I might be wrong but I tried


GalinKa [24]3 years ago
6 0
Divide the numerator into the denominator to get 0.425
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A girl has 3 different swimsuits, 4 different shorts and 3 different pairs of flip-flops. In how many different ways can this gi
In-s [12.5K]

Answer:

Option D is the correct answer.

Explanation:

 A girl has 3 different swimsuits, 4 different shorts and 3 different pairs of flip-flops.

 Different ways can this girl wear a swimsuit, a pair of short and a pair of flip-flops = 3P₁ x 4P₁ x 3P₁

               = 3 x 4 x 3

               = 36

  Different ways can this girl wear a swimsuit, a pair of short and a pair of flip-flops = 36

Option D is the correct answer.

4 0
3 years ago
The weight of an object on Planet X is twice that of its weight on Earth and one third of its weight on Planet Y. If an object o
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You see dont you think this hare...

Step-by-step explanation:

4 0
3 years ago
3 (2x-1) + 7 = -44 ( solve for x )
ollegr [7]
Multiply through the parenthesis:
6x - 3 = -51
Combine like terms:
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4 0
3 years ago
He purchased $12.00 worth of lemons and $4.00 worth of glasses to make the lemonade.
Allushta [10]

Answer:

<em>The minimum number of glasses of lemonade is 70</em>

Step-by-step explanation:

<u>Equations</u>

With the data provided, we can build a model for the profit that Michael gets for selling lemonade.

First, we set up the cost function. He purchased $12 in lemons and $4 in glasses. It makes a fixed cost of $16. He also spends $0.02 per glass of lemonade fot the sugar. Being x the number of glasses of lemonade Michael sells, the total cost is modeled by

C(x)=16+0.02x

The revenue for selling x glasses of lemonade is

R(x)=0.25x

The profit is

P(x)=R(x)-C(x)=0.25x-(16+0.02x)

P(x)=0.23x-16

To make profits:

0.23x-16>0

Solving for x

x>16/0.23

x>69.6

Since x must be an integer

The minimum number of glasses of lemonade is 70

7 0
3 years ago
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