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Katen [24]
3 years ago
8

HELP ME

Mathematics
1 answer:
navik [9.2K]3 years ago
7 0
$97.20 divided by $9.25 is 10 hours
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Karen planted a flower that was 14 inches tall. It grew 2 1/4 inches each week. If it is now 23 inches tall, how
NARA [144]

Answer:

4 weeks

Step-by-step explanation:

2 1/4 = 9/4 = 2.25

if it grows 2.25 inches in one week then in two weeks it would have grown 4.5 inches

keep adding the 2.25 inches to 14 until u get 23

:) hope this was heplful

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%2B%7Cx%2B1%7C%5C%20%5Ctextgreater%20%5C%200" id="TexFormula1" title="5x^{2}+|x+1|
Pavel [41]
5x² + |x+1| > 0
5x² + x + 1 > 0
x+1 > 0 because it came from absolute
5x² > 0 because it’s squared

When you try a number you should put it in the original equality
5x² + |x+1|
7 0
1 year ago
PLEASEEEEEEEEEEEEEEE HELP ME WILL GIVE BRAINLIST
miskamm [114]
The answer is 500 i think.
4 0
3 years ago
What to do with this question​
Katen [24]
Answer:

Explanation: there are
7 0
3 years ago
Consider an object moving along a line with the given velocity v. Assume t is time measured in seconds and velocities have units
Yakvenalex [24]

Answer:

a) positive direction: t < 2s & t>6s   ; negative direction: 2s < t < 6s

b) 7 m

c) 71 m

Step-by-step explanation:

Given:

v(t) = 3t^2 -24t +36   [0 , 7]

Find:

a) The value of time when particle is moving in positive direction:

The change in direction of the particle can be determined by v(t) > 0

Hence,

                                    0 < 3t^2 -24t +36

                                    0 < t^2 - 8t + 12

                                    0 < (t - 2)*(t - 6)

                                    t < 2s  , t  > 6s  

The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.

b) The displacement ds over the given interval [ 0 , 7 ]

                                  ds = integral (v(t)).dt

                                  ds = t^3 -12t^2 +36t

                                  ds = 7^3 -12*7^2 +36*7

                                  ds = 7 m

c) Total distance traveled in the interval:

                                 Total distance= ds(0-2) + ds(2-6) + ds(6-7)

                                 D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7

                                 D = 2*32 - 2*0 + 7

                                 D = 71 m          

     

6 0
3 years ago
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