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3 years ago

Who can help me answer this question ASAP please and thank you please show work

Mathematics

1 answer:

kotegsom [21]3 years ago

4 0

I'll do the first one to get you started

So we have g(f(x)) which means that we start with g(x) and replace the 'x' with 'f(x)' to get g(f(x))

g(x) = ( x - 4 )/2

g(f(x)) = ( f(x) - 4)/2 .... replace every x with f(x)

g(f(x)) = (2x+4-4)/2 .... replace f(x) on the right side with 2x+4

g(f(x)) = (2x+0)/2

g(f(x)) = (2x)/2

g(f(x)) = 1x/1

g(f(x)) = 1x

g(f(x)) = x

Let me know if you need help with the other one.

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4 years ago

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Step-by-step explanation:

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3 years ago

The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s

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Find the principal amount invested.

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t = time (in years)

Given:

I = Rs 320
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t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

Compound Interest Formula

$\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}$

where:

I = interest earned
P = principal amount
r = interest rate (in decimal form)
n = number of times interest applied per time period
t = number of time periods elapsed

Given:

P = 3200
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n = 1 (annually)
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Substitute the given values into the formula and solve for I:

$\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200$

$\implies \sf I=3200\left(1.05\right)^{2} -3200$

$\implies \sf I=3200\left(1.1025\right) -3200$

$\implies \sf I=3528-3200$

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