<img src="https://tex.z-dn.net/?f=2a%20-%204%20%5C2a%20%5Cdiv%20a%20-%202%20%5C3%20" id="TexFormula1" title="2a

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Delicious77 [7]

3 years ago

2 \3 " alt="2a - 4 \2a \div a - 2 \3 " align="absmiddle" class="latex-formula">
what the answer???

Mathematics

2 answers:

max2010maxim [7]3 years ago

6 0

It’s 2a-6 like the other person said you simplify the expression

grin007 [14]3 years ago

3 0

Simplify the expression.
2a − 6

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Tell whether each triangle with the given side lengths is a right triangle.

azamat

should be 60 cm if not it's 11

3 0

3 years ago

Use the quadratic formula to solve for x. 4x2 +9x-1=0

insens350 [35]

Answer:

$x=\frac{-9\pm\sqrt{65} }{8}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define

4x² + 9x - 1 = 0

Step 2: Define variables

a = 4

b = 9

c = -1

Step 3: Find roots

Substitute: $x=\frac{-9\pm\sqrt{9^2-4(4)(-1)} }{2(4)}$
Exponents: $x=\frac{-9\pm\sqrt{81-4(4)(-1)} }{2(4)}$
Multiply: $x=\frac{-9\pm\sqrt{81-16} }{8}$
Subtract: $x=\frac{-9\pm\sqrt{65} }{8}$

5 0

3 years ago

If the legs of a right triangle are 6 cm and 5 cm find the area of the triangle

Ilia_Sergeevich [38]

Answer: 15 cm²

Step-by-step explanation: To find the area of a triangle, start with the formula for the area of a triangle which is shown below.

$Area = \frac{1}{2}bh$

In this triangle, the base is 6 centimeters and the height is 5 centimeters. Now, plugging into the formula, we have $(\frac{1}{2})(6 cm)(5 cm)$ .

Now, it doesn't matter which order we multiply.

So we can begin by multiplying 1/2 times 6 cm and notice that the 2 in 1/2 and the 6 cross cancel to 1 and 3. So we're left with 3 cm.

Now, (3 cm)(5cm) is 15 cm².

So the area of the triangle is 15 cm².

6 0

3 years ago

What is the equation 6^2=36 in logarithmic

liq [111]

$log_{6}(36) = 2$

7 0

3 years ago

The coordinates of the verticals of a rectangle are (-3,4), (7,2), (6,-3), & (-4,-1). What is the perimeter of the rectangle

natali 33 [55]

Answer:

30.594

Step-by-step explanation:

To find perimeter we need to find the length of all the sides

The coordinates are A(-3,4), B(7,2), C(6,-3), D (-4,-1)

To find the length of side , we use distance formula

$Distance = \sqrt{(x2-x1)^2+(y2-y1)^2}$

Side $AB =\sqrt{(7--3)^2+(2-4)^2} = \sqrt{100+4}= \sqrt{104}=10.198$

Side $BC =\sqrt{(6-7)^2+(-3-2)^2} = \sqrt{1+25}= \sqrt{26}=5.099$

Side $CD =\sqrt{(-4-6)^2+(-1--3)^2} = \sqrt{100+4}= \sqrt{104}=10.198$

Side $DA =\sqrt{(-3--4)^2+(4--1)^2} = \sqrt{1+25}= \sqrt{26}=5.099$

To find perimeter we add all the sides

10.198 + 5.099 + 10.198 + 5.099= 30.594

the perimeter of the rectangle= 30.594

4 0

3 years ago