The probability of obtaining two blue marbles without replacement is equal to 0.15.
We are given that:
The number of yellow marbles = 3
Number of red marbles = 9
Number of Blue marbles = 8
Total marbles = 3 + 9 + 8
Total marbles = 20
Now, we have to calculate the probability of obtaining two blue marbles without replacement.
The probability will be:
P( obtaining two blue marbles without replacement ) = 8 / 20 × 7 / 19
P( obtaining two blue marbles without replacement ) = 56 / 380
P( obtaining two blue marbles without replacement ) = 0.15
Therefore, the probability of obtaining two blue marbles without replacement is equal to 0.15.
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Answer:
30
Step-by-step explanation:
To find the best prediction for the amount of numbered cards that will be drawn during the game, first find the probability of drawing a numbered card. There are 36 numbered cards and 48 total cards. So, the probability of drawing a numbered card is or .
Now, multiply the probability by the number of times a card will be drawn from the deck. Since there are 10 rounds and 4 players, a card will be drawn from the deck 10 × 4, or 40, times. So, multiply by 40.
Therefore, the best prediction for the amount of numbered cards that will be drawn during the game is 30.
Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8
b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4
Step-by-step explanation:
Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40
a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8
There are one in hundred million chances that the draw numbers are precisely the chosen ones.
b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)
8×32
P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.
There are approximately 300,000 chances that 7 of the players numbers are chosen
c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.
P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]
P(at least 6 players numbers are drawn) = 1.84×10^-4.
There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.
Answer:
it would be 98 degrees
Step-by-step explanation:
if 2 lines inersect it means you create 4 angles. 2 of those angles are the same as well as the other ones so if one is 82 then the angle that counters it is 98
82+98=180
180 degrees equals line
