All categories

3 years ago

They are asking me to find the lcm of 6x2zy3,9x3y2z2,4x2z

Mathematics

1 answer:

Dimas [21]3 years ago

3 0

Answer:

01133456385652+3+563206+5++323512652+52+56262626+52626256262625151561561215615165546465436465643436454663546463463894834983543875349753957935748459548948957438754893573985839459853857438548958488388888844444444444444238373985348489179487788

Step-by-step explanation:

Read more about bisectors at:

brainly.com/question/6725549

#SPJ1

8 0

2 years ago

What is the answer please help

ExtremeBDS [4]

Answer:

Step-by-step explanation:

thw answer is on the picture

4 0

3 years ago

Leo drew a line that is perpendicular to the line shown on the grid and passes through point (F. G). Which of the following is t

tensa zangetsu [6.8K]

The equation of the perpendicular line drawn by Leo is $y-G=\dfrac{-1}{2}(x-F)$ . Option C is the correct answer.

<h3>How to determine the equation of a line?</h3>

A line is drawn perpendicular to the line shown in the image. The perpendicular line passes through the coordinate point (F,G).

The slope of the line from the graph is-

$m=\dfrac{y-intercept}{x-intercept}\\\\\\m=2$

Therefore, the slope of the perpendicular line is $\dfrac{-1}{2}$ .

Also, it is being given that Leo's line is passing through the coordinate point .

So, the equation of the Leo's line is-

$y-G=\dfrac{-1}{2}(x-F)$

Thus, the equation of the perpendicular line drawn by Leo is .

$y-G=\dfrac{-1}{2}(x-F)$

Learn more about the equation of line here- brainly.com/question/20632687

#SPJ1

7 0

2 years ago

Consider the quadratic function f(x)=−x^2+x+30

yaroslaw [1]

Answer:

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The yy-intercept is $y = 30$ .

Step-by-step explanation:

Given a quadratic function in the following format:

$f(x) = ax^{2} + bx + c = 0, a \neq 0$

The x-values of the x-intercepts are $x_{1}, x_{2}$ , given by the following formulas.

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

We have that:

$f(x) = -x^{2} + x + 30$

This is not in the format above. I will multiply by (-1), so we have:

$f(x) = x^{2} - x - 30$

So, $a = 1, b = -1, c = -30$

$\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121$

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6$

$x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5$

This means that

The smallest xx-intercept is $x = -5$

The largest xx-intercept is $x = 6$

The y-intercept is the value of f(x) when x = 0. So

$f(x)=−x^{2}+x+30$

$f(0) = 30$

The yy-intercept is $y = 30$ .

5 0

3 years ago

If a hurricane was headed your way, would you evacuate? The headline of a press release issued January 21, 2009 by the survey re

Nikolay [14]

Answer:

The 98% confidence interval for population proportion of people who refuse evacuation is {0.30, 0.33].

Step-by-step explanation:

The sample drawn is of size, n = 5046.

As the sample size is large, i.e. n > 30, according to the Central limit theorem the sampling distribution of sample proportion will be normally distributed with mean $\hat p$ and standard deviation $\sqrt{\frac{\hat p (1-\hat p)}{n} }$ .

The mean is: $\hat p=0.31$

The confidence level (CL) = 98%

The confidence interval for single proportion is:

$CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]$

Here $z_{(\alpha /2)}$ = critical value and α = significance level.

Compute the value of α as follows:

$\alpha =1-CL\\=1-0.98\\=0.02$

For α = 0.02 the critical value can be computed from the z table.

Then the value of $z_{(\alpha /2)}$ is ± 2.33.

The 98% confidence interval for population proportion is:

$CI_{p}=[\hat p-z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} },\ \hat p+z_{(\alpha /2)}\times\sqrt{\frac{\hat p (1-\hat p)}{n} }]\\=[0.31-2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} },\ 0.31+2.33\times \sqrt{\frac{0.31\times(1-0.33)}{5046} } ]\\=[0.31-0.0152,\ 0.31+0.0152]\\=[0.2948,0.3252]\\\approx[0.30,\ 0.33]$

Thus, the 98% confidence interval [0.30, 0.33] implies that there is a 0.98 probability that the population proportion of people who refuse evacuation is between 0.30 and 0.33.

7 0

3 years ago