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1 year ago

Point A bisects LS BC. If LS BA=6x-3 and LS AC= 3x+7. Solve for X. PLS ANSWER QUICKLY!!!

Mathematics

1 answer:

denis23 [38]1 year ago

8 0

Based on the bisection of line BC by point A, the value of x is 10/3

<h3>How to determine the value of x?</h3>

The given parameters are:

Point A bisects BC
BA = 6x - 3
AC= 3x + 7

Because the point A bisects BC, then

BA = AC

Substitute the known values in the above equation

So, we have

6x - 3 = 3x + 7

Collect the like terms

6x - 3x = 3 + 7

Evaluate the like terms

3x = 10

Divide both sides of the equation by 3

x = 10/3

Hence, based on the bisection of line BC by point A, the value of x is 10/3

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3 years ago

Solve for x. 5(x – 10) = 30 – 15x

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Hey!

The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

Original Equation :
5 ( x - 10 ) = 30 - 15x

New Equation {Changed by Distribution} :
5x - 50 = 30 - 15x

The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

Old Equation :
5x - 50 = 30 - 15x

New Equation {Changed by Adding 50 to Both Sides} :
5x = 80 - 15x

And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.

Old Equation :
5x = 80 - 15x

New Equation {Changed by Adding 15x to Both Sides} :
20x = 80

Now we divide both sides by 20 to get x on it's own.

Old Equation :
20x = 80

New Equation {Changed by Dividing Both Sides by 20} :
$\frac{20x}{20}$ = $\frac{80}{20}$

Finally, all we have to do is solve to find x.

Old Equation :
$\frac{20x}{20}$ = $\frac{80}{20}$

Solution {Old Equation Solved} :
x = 4

So, in the equation 5 ( x – 10 ) = 30 – 15x, x = 4.

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