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1 year ago

Point A bisects LS BC. If LS BA=6x-3 and LS AC= 3x+7. Solve for X. PLS ANSWER QUICKLY!!!

Mathematics

1 answer:

denis23 [38]1 year ago

8 0

Based on the bisection of line BC by point A, the value of x is 10/3

<h3>How to determine the value of x?</h3>

The given parameters are:

Point A bisects BC
BA = 6x - 3
AC= 3x + 7

Because the point A bisects BC, then

BA = AC

Substitute the known values in the above equation

So, we have

6x - 3 = 3x + 7

Collect the like terms

6x - 3x = 3 + 7

Evaluate the like terms

3x = 10

Divide both sides of the equation by 3

x = 10/3

Hence, based on the bisection of line BC by point A, the value of x is 10/3

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3 years ago

What ratio is proportional to 18/21

Doss [256]

Answer:

There are many.

Step-by-step explanation:

When you say proportional, you are looking for a ratio that is equivalent to the ratio given. In your case, there are many so you might need to be more specific. But still, we can help you figure it out.

An easy way to do this would be to scale it down to its simplest form and then move upwards. To find proportional ratios, just multiply denominator and the denominator with the same factor.

$\dfrac{18}{21} = \dfrac{6}{7}$

That is your ratio in its simplest form. Now we can scale up, I'll show you how to do one completely:

$\dfrac{6}{7} x \dfrac{2}{2} = \dfrac{12}{14}$

That's the same ratio scaled up by a factor of 2.

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$\dfrac{6}{7} x \dfrac{3}{3} = \dfrac{18}{21}$

That's the ratio given

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$\dfrac{6}{7} x \dfrac{4}{4} = \dfrac{24}{28}$

Scaled up by a factor of 4

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$\dfrac{6}{7} x \dfrac{5}{5} = \dfrac{30}{35}$

Scaled up by a factor of 5.

The list goes on and on.

3 0

3 years ago

For a certain candy, 20% of the pieces are yellow, 15% are red, 20% are blue, 20% are green, and the rest are brown. a

OLEGan [10]

Answer:

Step-by-step explanation:

Based on the question we are given the percentages of each of the types of candies in the bag except for brown. Since the sum of all the percentages equals 75% and brown is the remaining percent then we can calculate that brown is (100-75 = 25%) 25% of the bag. Now we can show the probabilities of getting a certain type of candy by placing the percentages over the total percentage (100%).

Brown: $\frac{25}{100}$
Yellow or Blue: $\frac{20}{100} +\frac{20}{100} = \frac{40}{100}$ ....add the numerators

Not Green: $\frac{80}{100}$ .... since the sum of all the rest is 80%

Stiped: $\frac{25}{100}$ .... there are 0 striped candies.

Assuming the <u><em>ratios/percentages</em></u> of the candies stay the same having an infinite amount of candy will not affect the probabilities. That being said in order to calculate consecutive probability of getting 3 of a certain type in a row we have to multiply the probabilities together. This is calculated by multiplying the numerators with numerators and denominators with denominators.