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Mamont248 [21]
3 years ago
5

True or False? It is impossible to circumscribe a circle about the quadrilateralbelow.​

Mathematics
2 answers:
lara31 [8.8K]3 years ago
7 0

Answer: False

Step-by-step explanation:

bazaltina [42]3 years ago
7 0

Answer:

False

Step-by-step explanation:

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Please helpppp I will give you a brainleist !!!!!! ​
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Answer:

Hope this helps

Step-by-step explanation:

4. 10^2

5. 64 / 14 * 9 + 8

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6.   1.762 x 10^3

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3 years ago
The measures of complementary angles have a sum of 90 degrees.Angle A and angle B are complimentary, and their measures have a d
777dan777 [17]

Answer:

The measure of the angles are 55° and 35°

Step-by-step explanation:

Sum of two angles that are complement of each other are 90.

The angles are A and B, so we can write:

A + B = 90

Also,

The difference is 20. Let A be the greater of them, so we can write equation 2 as:

A - B = 20

Now, we add up both equations, eliminate B and solve for A first:

A + B = 90

A - B = 20

---------------

2A = 90 + 20

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A = 110/2

A = 55

And now the measure of B:

A + B = 90

55 + B = 90

B = 90 - 55

B = 35

5 0
4 years ago
If x equals 8-(-2.25) and y equals 6-4.2-(-4.9) what is the value of x-y
natta225 [31]

x = 8-(-2.25) = 8+2.25 = 10.25

y = 6-4.2-(-4.9)=6-4.2+4.9=6+0.7=6.7

<span>x-y = 10.25.-6.7= \frac{1025}{100} - \frac{670}{100} = \frac{1025-670}{100} = \frac{355}{100} =3.55</span>

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4 years ago
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ladessa [460]

Answer:

Step 3: Choice D

Step 5: Choice B

Step 6: Choice A

Step 8: Choice C

(I saw in the top left corner of the picture that this is for Algebra II. I am in 8th grade, currently taking geometry, and I haven't taken Algebra II yet, but I <em>did</em> take Algebra I last year. I am 95% sure this is correct but if it isn't, the I sincerely apologize.)

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3 years ago
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