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2 years ago

True or False? It is impossible to circumscribe a circle about the quadrilateralbelow.

Mathematics

2 answers:

lara31 [8.8K]2 years ago

7 0

Answer: False

Step-by-step explanation:

bazaltina [42]2 years ago

7 0

Answer:

False

Step-by-step explanation:

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What's The slope intercept form of: x - y = 7

Brilliant_brown [7]

Y=x-7 this is because you subtracted the x to both sides. Since y is a negative, you divide by -1 causing the -x to turn positive and the positive seven to be negative seven.

5 0

3 years ago

20 points!!

ANEK [815]

See below for the proof of the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

<h3>How to prove the equation?</h3>

The equation is given as:

$\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$

Take the LCM

$\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)$

Expand

$\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)$

Evaluate the like terms

$\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)$

Rewrite as:

$\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)$

Factorize the numerator

$\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)$

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation $\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)$ has been proved

Read more about equations at:

brainly.com/question/2972832

#SPJ1

5 0

1 year ago

What is the rule

Taya2010 [7]

Add 5

y is found by adding 5 to x

5 0

2 years ago

Use circle C<br><br> classify arc MNO in circle C

inna [77]

Answer:

Semicircle

Step-by-step explanation:

As we can see, the arc is bounded by the chord MO

since the chord passes through the center of the circle, we have it that the chord is a diameter

Mathematically, an arc bounded by a diameter represents half of a circle

So we can conclude that the arc MNO in circle C is a semicircle

5 0

2 years ago

PLZ HELP PLZ HELP

ankoles [38]

Answer:

Step-by-step explanation:

3 0

2 years ago

True or False? It is impossible to circumscribe a circle about the quadrilateralbelow.​

True or False? It is impossible to circumscribe a circle about the quadrilateralbelow.