Answer:
The speed of a wave depends on the characteristics of the medium. For example, in the case of a guitar, the strings vibrate to produce the sound. The speed of the waves on the strings, and the wavelength, determine the frequency of the sound produced. The strings on a guitar have different thickness but may be made of similar material. They have different linear densities, where the linear density is defined as the mass per length,
μ
=
mass of string
length of string
=
m
l
.
In this chapter, we consider only string with a constant linear density. If the linear density is constant, then the mass
(
Δ
m
)
of a small length of string
(
Δ
x
)
is
Δ
m
=
μ
Δ
x
.
For example, if the string has a length of 2.00 m and a mass of 0.06 kg, then the linear density is
μ
=
0.06
kg
2.00
m
=
0.03
kg
m
.
If a 1.00-mm section is cut from the string, the mass of the 1.00-mm length is
Δ
m
=
μ
Δ
x
=
(
0.03
kg
m
)
0.001
m
=
3.00
×
10
−
5
kg
.
The guitar also has a method to change the tension of the strings. The tension of the strings is adjusted by turning spindles, called the tuning pegs, around which the strings are wrapped. For the guitar, the linear density of the string and the tension in the string determine the speed of the waves in the string and the frequency of the sound produced is proportional to the wave speed.
Answer:
378
Step-by-step explanation:
It will also be a multiple of 21 .
As it is divisible by 3 the first possibility is 366 so:-
364 + n = 21m
where n = 2,5,8,11,14...
Trying each number in turn we get:-
364 + 14 = 21m
21m = 378
m = 18
so the answer is 378
to get the the equation of any straight line, we only need two points off of it, let's use the two points already in the picture.
Answer:
each 200 acres.
Step-by-step explanation:
Here we are given 2000 profit for wheat per acre and 3000 profit per acre for corn.
Hence objective function to maximize is
Where W is wheat cultivated and C, corn cultivated
Constraints are workers and acres
Total workers required = 3W+2C and total fertilizers = 2w+4c
We solve and get corner points as
(W,C) = (333,0) (600,0) (0,500) (0,300)
Intersecting point is
by solving we get
2w = 400 or w =200 and c = 200
Thus feasible points are
(200,200) Or (333,0) or (0,300)
Z for I point = 1000000
Z for II point = 666000
Z for III point =900000
Maximum is when wheat and corn are 200 acres each planted.
3. 7 times 3 equals 21 and 21+25=46.
