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3 years ago

What is the solution set of the following equation? -5x + x + 9 = -4x + 12

1 answer:

7 0

A linear equation with one variable, x, is an equation that can be written in the standard form a x+b=0 where a and b are real numbers and a≠0. For example. 3x−12=0. A solution to a linear equation is ...Answer:

Step-by-step explanation:A linear equation with one variable, x, is an equation that can be written in the standard form a x+b=0 where a and b are real numbers and a≠0. For example. 3x−12=0. A solution to a linear equation is ...

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I dont understand this

MrRa [10]

Answer: First option.

Step-by-step explanation:

You need to remember the following Trigonometric Identity:

$cos\alpha =\frac{adjacent}{hypotenuse}$

In this case, you can identify in the figure that:

$\alpha =35\°\\adjacent=9\\hypotenuse=x$

Then you must substitute these values into $cos\alpha =\frac{adjacent}{hypotenuse}$ :

$cos(35\°) =\frac{9}{x}$

Finally, you need to solve for "x" in order to find its value. This is:

$(x)(cos(35\°))=9\\\\x=\frac{9}{cos(35\°)}\\\\x=10.98$

Rounding the result to the nearest tenth, you get:

$x\approx11$

8 0

3 years ago

What is the answer to this problem

mr_godi [17]

Answer:

I think its the second one

Step-by-step explanation:

the other ones are fair and have a 50% chance on choosing.

I am so srry if I'm wrong but I'm pretty confident.

7 0

2 years ago

Read 2 more answers

If a square has a side length of 11, what is the area

aliina [53]

121 is the area of the square

4 0

2 years ago

Read 2 more answers

Evaluate: 36/x - 5 X=4

laiz [17]

Answer:

the answer is four

Step-by-step explanation:

Because first you do 36/4 which gets you to 9 and then subtract it by 5 to get 4!

5 0

2 years ago

Read 2 more answers

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } }$ , $5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } }$ ]

= [5.10 , 5.20]

Therefore, 95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0

3 years ago