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sladkih [1.3K]
2 years ago
6

Please help me please help me please help me please help me please help me please help me please​

Mathematics
1 answer:
natali 33 [55]2 years ago
5 0

Answer:

for the first one it's 40 seconds

and for the second one I can't see the options but I I think it is 300

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What’s 112/250 simplified
svp [43]

Answer:

\frac{56}{125}

Step-by-step explanation:

112/250

Reduce the fraction \frac{112}{250} to the lowest terms by extracting and canceling out 2.

\frac{56}{125}

Hope it helps and have a great day! =D

~sunshine~

3 0
2 years ago
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Jordan received 30 text messages from his friends and 18 text messages from his parents. Write the radio that compares the numbe
maksim [4K]

Answer:

The answer is 5:3 if I'm correct

6 0
3 years ago
If a3 = 11 and a5 = 7 and ak is the -th term of the sequence and ak = -9, then what is the value of k?
babymother [125]
An=a3+d

-9=11+-2

2n=26

n=13
6 0
3 years ago
How to do this problem
borishaifa [10]

5. since 2/3 cups goes into 1 tortilla , if she finds out how many 1/3 cups go into 8 cups, she would need to divide that amount

6, since it takes less than 1 cup for each tortilla, she should be able to fill more than 8

8 0
2 years ago
"Immediately after a ban on using hand-held cell phones while driving was implemented, compliance with the law was measured. A r
sergiy2304 [10]

Answer:

(a) Null Hypothesis, H_0 : p_1-p_2=0  or  p_1= p_2  

    Alternate Hypothesis, H_A : p_1-p_2\neq 0  or  p_1\neq p_2

(b) We conclude that there is a statistical difference in these two proportions measured initially and then one year later.

Step-by-step explanation:

We are given that a random sample of 1,250 drivers found that 98.9% were in compliance. A year after the implementation, compliance was again measured to see if compliance was the same (or not) as previously measured.

A different random sample of 1,100 drivers found 96.9% compliance."

<em />

<em>Let </em>p_1<em> = proportion of drivers that were in compliance initially</em>

p_2<em> = proportion of drivers that were in compliance one year later</em>

(a) <u>Null Hypothesis</u>, H_0 : p_1-p_2=0  or  p_1= p_2      {means that there is not any statistical difference in these two proportions measured initially and then one year later}

<u>Alternate Hypothesis</u>, H_A : p_1-p_2\neq 0  or  p_1\neq p_2     {means that there is a statistical difference in these two proportions measured initially and then one year later}

The test statistics that will be used here is <u>Two-sample z proportion statistics</u>;

                     T.S.  = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{ \frac{\hat p_1(1-\hat p_1)}{n_1} + \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of drivers in compliance initially = 98.9%

\hat p_2 = sample proportion of drivers in compliance one year later = 96.9%

n_1 = sample of drivers initially = 1,250

n_2 = sample of drivers one year later = 1,100

(b) So, <u><em>the test statistics</em></u>  =  \frac{(0.989-0.969)-(0)}{\sqrt{ \frac{0.989(1-0.989)}{1,250} + \frac{0.969(1-0.969)}{1,100}} }  

                                           =  3.33

<u>Now, P-value of the test statistics is given by;</u>

         P-value = P(Z > 3.33) = 1 - P(Z \leq 3.33)

                                            = 1 - 0.99957 = <u>0.00043</u>

Since in the question we are not given with the level of significance so we assume it to be 5%. Now at 5% significance level, the z table gives critical values between -1.96 and 1.96 for two-tailed test.

<em>Since our test statistics does not lies within the range of critical values of z, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><u><em>we reject our null hypothesis.</em></u>

Therefore, we conclude that there is a statistical difference in these two proportions measured initially and then one year later.

7 0
3 years ago
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