Answer:
Three hundred eighty two
Step-by-step explanation:
Step-by-step explanation:
<h3><u>Given :-</u></h3>
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
<h3>
<u>Required To Prove :-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Proof :-</u></h3>
On taking LHS
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
We know that
Tan θ = 1/ Cot θ
and
Cot θ = 1/Tan θ
=> (1+Cot²θ)(1+Tan²θ)
=> (Cosec² θ) (Sec²θ)
Since Cosec²θ - Cot²θ = 1 and
Sec²θ - Tan²θ = 1
=> (1/Sin² θ)(1/Cos² θ)
Since , Cosec θ = 1/Sinθ
and Sec θ = 1/Cosθ
=> 1/(Sin²θ Cos²θ)
We know that Sin²θ+Cos²θ = 1
=> 1/[(Sin²θ)(1-Sin²θ)]
=> 1/(Sin²θ-Sin²θ Sin²θ)
=> 1/(Sin²θ - Sin⁴θ)
=> RHS
=> LHS = RHS
<u>Hence, Proved.</u>
<h3><u>Answer:-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Used formulae:-</u></h3>
→ Tan θ = 1/ Cot θ
→ Cot θ = 1/Tan θ
→ Cosec θ = 1/Sinθ
→ Sec θ = 1/Cosθ
<h3><u>Used Identities :-</u></h3>
→ Cosec²θ - Cot²θ = 1
→ Sec²θ - Tan²θ = 1
→ Sin²θ+Cos²θ = 1
Hope this helps!!
Answer:
D. No, Jacob is not correct. The median amount he makes is $84.00 in a day.
Step-by-step explanation:
In this case, the mean is not the best measure of this data.
We can see that there is one value lower than the rest, $58. This brings the mean down.
With the value of $58, the mean is $80.70. If we were to take this value out, the mean would be $85.20, which is higher.
Since the mean is brought down by this value, we should use the median. The median of this data set is $84.
Hi,
Get knowledge *throw math book at brain*
8 x 8 x 8 is 512 so its not a or b, add that to 6 times 6 and it equals d 546,
Answered by Britton have a nice day:)
5 roach motels per square yd
A = L * W
A = 7 * 4
A = 21 square yds
so if they set out 5 roach motels per square yd, then they need to set out :
5 * 21 = 105 roach motels <==
