<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
Answer:
Radius, r = 61 cm
Step-by-step explanation:
According to the attached figure, we have,
Length of chord, AB = 22 cm
Such that, AP = PB = 11 cm
OP = 60 cm
It is required to find the radius of the circle. We know that radius of a circle is perpendicular to chord. So, APO forms a right angled triangle. Using Pythagoras theorem to find the radius of circle. Let it is r. So,
So, the radius of the circle is 61 cm.
The answer is <u>0.001213 mi</u>
600x1.07^11 = 1262
11 Months
Answer:
d
Step-by-step explanation:
