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gtnhenbr [62]
3 years ago
5

Jake ate 1/6 of the chocolates the Jill came ate 1/5 of the remaining then mike ate 1/4 of the remaining then Sara ate 1/3 of th

e remaining and Luke ate 1/2 of what was left. I came home and there was 4 chocolate left. How many did jake eat?
Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

  4 chocolates

Step-by-step explanation:

Before Luke started eating, there were 8. This is 2/3 of what Sara had to start with, so she started with 12. That is 3/4 of what Mike started with, so he started with 16.

Jill left 4/5 of what she started with, so she must have started with 20. Jake ate 1/6 and left 5/6, so 20 is 5 times the number Jake ate.

Jake ate 4 chocolates.

___

Jill ate 4; Mike ate 4; Sara ate 4; and Luke ate 4.

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3 0
3 years ago
Co-ordinate Geometry
saul85 [17]

Answer:

The value of a  = 14

Step-by-step explanation:

Given

(x₁, y₁) = (2, 4)

(x₂, y₂) = (6, a)

(x₃, y₃) = (-1, 1)

A = 9 sq.units

Area of a triangle with vertices (x₁, y₁), (x₂, y₂), and (x₃, y₃) is:

A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}

substituting the values (x₁, y₁) = (2, 4), (x₂, y₂) = (6, a), (x₃, y₃) = (-1, 1), A = 9 in th formula

A=\frac{\left|x_1\left(y_2-y_3\right)+x_2\left(y_3-y_1\right)+x_3\left(y_1-y_2\right)\right|}{2}

9=\frac{\left|2\left(a-1\right)+6\left(1-4\right)+-1\left(4-a\right)\right|}{2}

Multiply both sides by 2

\frac{2\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|}{2}=9\cdot \:2

simplify

\left|2\left(a-1\right)+6\left(1-4\right)-1\left(4-a\right)\right|=18

As the area is always positive.

so

2\left(a-1\right)+6\left(1-4\right)-1\cdot \left(4-a\right)=18

2\left(a-1\right)-18-\left(4-a\right)=18

Add 18 to both sides

2\left(a-1\right)-18-\left(4-a\right)+18=18+18

simplify

2\left(a-1\right)-\left(4-a\right)=36

3a-6=36

3a=42

Divide both sides by 3

\frac{3a}{3}=\frac{42}{3}

a=14

Thus, the value of a  = 14

7 0
3 years ago
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