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gtnhenbr [62]
3 years ago
5

Jake ate 1/6 of the chocolates the Jill came ate 1/5 of the remaining then mike ate 1/4 of the remaining then Sara ate 1/3 of th

e remaining and Luke ate 1/2 of what was left. I came home and there was 4 chocolate left. How many did jake eat?
Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Answer:

  4 chocolates

Step-by-step explanation:

Before Luke started eating, there were 8. This is 2/3 of what Sara had to start with, so she started with 12. That is 3/4 of what Mike started with, so he started with 16.

Jill left 4/5 of what she started with, so she must have started with 20. Jake ate 1/6 and left 5/6, so 20 is 5 times the number Jake ate.

Jake ate 4 chocolates.

___

Jill ate 4; Mike ate 4; Sara ate 4; and Luke ate 4.

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Answer:

a) a(t)= 6.27e^{0.0147*t}

b) 6.84 million

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Step-by-step explanation:

a)Here we know standard exponential growth rate is

a(t)= ae^{k*t}

In this put t=0 and a(t)=6.27 million

thus we get a = 6.27 million

now \frac{da}{dt}=a(t)k

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b)Put t = 6

we get

a(t)= 6.27e^{0.0147*6}

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we get 16.52 years

d) 2*6.27=6.27e^{0.0147*t}

take log both sides we get 47 years to get double the current population.

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3 years ago
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