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Vesna [10]
3 years ago
8

-

e" class="latex-formula">x=\frac{2}{3}
-4/9x=2/3

Mathematics
2 answers:
sammy [17]3 years ago
7 0
The answer to this math problem is 6/-4
Katarina [22]3 years ago
6 0

Answer:

x = -\frac{6}{4}

Step-by-step explanation:

<u>Method 1:</u>

1. Original Equation: -\frac{4}{9}x = \frac{2}{3}

2. Multiply by 9 on both sides: -\frac{4 * 9}{9}x =  \frac{2 * 9}{3}

Whatever you do to one side you have to do to the other. You would multiply by 9 on both sides because the LCD of 3 and 9 is 9. You want to make it where you can get rid of the fraction.

3. Simplify: -\frac{36}{9}x = \frac{18}{3}

Simplify the numerators of both fractions.

4. Simplify: -4x = 6

Divide both of your fractions to simplify them.

5. Divide: x = -\frac{6}{4}

Divide by -4 on both sides to get x by itself.

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3 years ago
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The length of a rectangular piece of land is 9 cm more than 3 times its width. The perimeter is 418 cm. Find its dimensions.
SashulF [63]

Let w represent the width of the rectangle in cm. Then its length in cm is (3w+9). The perimeter is the sum of two lengths and two widths, so is ...

... 418 = 2(w + (3w+9))

... 209 = 4w +9 . . . . . . divide by 2, collect terms

... 200 = 4w . . . . . . . . subtract 9

... 50 = w . . . . . . . . . . divide by 4

... length = 3w+9 = 3·50 +9 = 159

The dimensions of this piece of land are 159 cm by 50 cm.

3 0
3 years ago
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belka [17]
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3 0
3 years ago
Can someone help me with this?? If you can't see the picture don't bother to answer.
Georgia [21]
J is correct. the scale is balanced, so x = 1. there are 9 1’s on the right, and 6 1’s on the left. there are 3 more blocks, and they would have to each be 1.
7 0
3 years ago
Priya's cat weighs 5 1/2 pounds and her dog weighs 8 1/4 pounds.
Lilit [14]

Answer: The cat is 2/3 times as heavy as the dog.


Step-by-step explanation:

The weight of Priya's cat =5\frac{1}{2}\ pounds

Now, 5\frac{1}{2}=\frac{11}{2}\ pounds

The weight of her dog =8\frac{1}{4}\ pounds

8\frac{1}{4}=\frac{33}{4}\ pounds

Let cat is n times heavy as dog.

Then n=\text{cat's weight}\div\text{dog's weight}

n=\frac{{11}{2}\div\frac{33}{4}\\\Rightarrow\ n=\frac{11}{2}\times\frac{4}{33}\\\Rightarrow\ n=\frac{2}{3}

Hence, The cat is 2/3 times as heavy as the dog.

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3 years ago
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