Can someone answer this please?

Mathematics

2 answers:

SOVA2 [1]3 years ago

8 0

We can break this complicated looking shape into two more familiar ones, an icosoles triangle and a rectangle. Using the area of a triangle formula (base*height)/ 2, we get (3*6)/2=18/2= 9. Next, we multiply 8 by 16 to solve for the rectangle and get 128. We add 9 and 128 to get 137.

Your answer is 137.

Masja [62]3 years ago

5 0

Hey there! :)

First, find the area of the rectangle

Formula = l · w

l = 16
w = 8

16 · 8 = 128

Now, find the area of the triangle

Formula = (b · h) ÷ 2

b = 3
h = 6

(6 · 3) ÷ 2
↓
18 ÷ 2 = 9

Now, add both areas

128 + 9 = 137

The area is 137 sq. ft

Hope this helps :)

You might be interested in

three trigonometric functions for a given angle are shown below csc theta = 13/12, sec theta = -13/5, cot theta = -5/12 what are

goldenfox [79]

We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12

we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13

sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13

sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant

therefore
the coordinates of point (x,y) on the terminal ray of angle theta are
x=-5
y=12

the answer is
point (-5,12)

see the attached figure