Answer:
For the value of hypotenuse can be irrational, sum of squares of other two legs might be imperfect square number.
Step-by-step explanation:
We all know, the Pythagorean theorem can be stated as follows:
The sum of squares of two legs of a right angled triangle is equal to the square of the hypotenuse.
i.e.
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
Where,
is the hypotenuse and
are the two other legs of the right angled triangle.
Given that:
and
are rational numbers.
To find:
Situation for which
is irrational.
Square of a rational number is always rational.
So,
both will be rational.
And sum of squares of two rational numbers will also be rational.
Therefore,
will also be rational.
and
![c = \sqrt{a^2+b^2}](https://tex.z-dn.net/?f=c%20%3D%20%5Csqrt%7Ba%5E2%2Bb%5E2%7D)
For the value of
can be irrational, sum of squares of other two legs might be imperfect square number.