All categories

3 years ago

What is the equation of the line that has a slope of -4 and passes through ( 9, -5)

Mathematics

1 answer:

11111nata11111 [884]3 years ago

6 0

Answer:

y = -4x + 31

Step-by-step explanation:

y = mx + b

y = -4x + b

-5 = -4(9) + b

-5 = -36 + b

b = 31

You might be interested in

Which four points are coplanar

jenyasd209 [6]

Answer:

B, A, F, H

Step-by-step explanation:

8 0

2 years ago

Just give answers to blanck ones just give me The answers cause I don't want no explaining because I'm Savage

Airida [17]

Omg wow bruh #savageaf

6 0

3 years ago

Read 2 more answers

Hi, I need to send an drawing

lina2011 [118]

Answer:

Ok then send the drawing

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Triangle ABC has vertices at A(−1 , 2), B(4, 2), and C(3, −1). Classify the triangle according to the side lengths.

Orlov [11]

Answer:

B) Isosceles

Step-by-step explanation:

The given triangle has vertices at A(-1,2), B(4,2) and C(3,-1).

We must first determine the length of the sides of the triangle, before we can classify it.

We apply the distance formula to find length of the sides.

$|AB|=\sqrt{(4--1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{(4+1)^2+(2-2)^2}$

$\Rightarrow |AB|=\sqrt{5^2+(0)^2}$

$\Rightarrow |AB|=\sqrt{25}$

$\Rightarrow |AB|=5 units$ .

The length of side BC

$|BC|=\sqrt{(3-4)^2+(-1-2)^2}$

$\Rightarrow |BC|=\sqrt{(-1)^2+(-3)^2}$

$\Rightarrow |BC|=\sqrt{1+9}$

$\Rightarrow |BC|=\sqrt{10}$

The length of side AC

$|AC|=\sqrt{(3--1)^2+(-1-2)^2}$

We simplify to obtain;

$|AC|=\sqrt{(3+1)^2+(-3)^2}$

$\Rightarrow |AC|=\sqrt{(4)^2+(-3)^2}$

$|AC|=\sqrt{16+9}$

$|AC|=\sqrt{25}$

$|AC|=5\:units$

Since $|AC|=5\:units=|AB|$ , the given triangle is an isosceles triangle.

The correct answer is

6 0

3 years ago

Read 2 more answers

The ratio of coretta's weight to Justin's weight is 3:4. If corretta gains 5 pounds the ratio of their weights will be 4:5. How

Verdich [7]

Answer:

100 pounds

Step-by-step explanation:

4 0

2 years ago