Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula

![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)





Therefore, x=0 and x=3
But last step in the given solution

It is wrong this property is used when
then

Hence, the student wrote
instead of
and solution is given by
x=0 and x=3
Well its a simplest form of zero and 6 tenths and if u divide it by 2 youll get 3/5 as a fraction
In the equation you have to replace all x's with -1
f (-1) = (-1)^2 - 8(-1) +5
f (-1) = 1 + 8 + 5
f (-1) = 14
the f(-1) stand for the function of -1. it is also equivalent to y
Answer:
Step-by-step explanation:
11 - 19 - 4 - (-8) =
11 - 19 - 4 + 8 =
- 23 + 19 =
- 4 <===
Answer: correct answer is B.(2x+3y)(4x^2-6xy+9y^2)
8x^3 + 27y^3
(2x)^3+(3y)^3
(2x+3y)(4x^2-6xy+9y^2) <----answer