The number of times Ken visits, given the £3.6 pool charge, and 1/3 savings per visit is 5 times.
<h3>Which method can be used to find the number of times Ken visits the pool to get back his £5?</h3>
The entry fee = £3.60
Amount saved on entry fee by having a membership card = 1/3 of the entry fee
Amount Ken spends on the membership card and the reduced entry fee = £5
Therefore;
Reduced entry fee = £3.60×(1 - 1/3) = £2.4
Amount saved per visit = £3.6 - £2.4 = £1.2
The number of visits, <em>n</em>, before he gets back his £5 is therefore;
- n = £5/(£1.2/visit) ≈ 4.17 visits
Ken has to visit the swimming pool more than 4 times to get his £5 back.
Rounding to the next larger whole, therefore;
- The number of visits, n, before he gets back his £5 is 5 visits
Learn more about fractions here:
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256*16 is the correct answer here.
The chances for my friend to be in my group are low given the probability, I say no.
You will be using Pythagoras so the setup will be in the image
Answer:
<em>b = 12 cm</em>
Step-by-step explanation:
<u>The Pythagora's Theorem</u>
The area of a square of side length x is
We have three squares, two of which have side lengths of a=5 cm and b= 13 cm.
The combined area of the smaller squares is the same as the area of the largest square. We cannot say at first sight which square is the largest, we'll assume the square of side length of 13 cm is the largest one. Thus:
Where b is the unknown side length.
The above expression corresponds to the Pythagora's Theorem formula. Solving for b:
b = 12 cm
