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Karolina [17]
3 years ago
9

Suppose you increase your walking speed from 6s to 12 m/s in a period of 2 s. What is acceleration

Physics
1 answer:
ElenaW [278]3 years ago
5 0

As we know that acceleration is given as

a = \frac{v_f - v_i}{t}

here we know that

v_i = 6 m/s

v_f = 12 m/s

\Delta t = 2 s

now we will have

a = \frac{12 - 6}{2}

a = 3 m/s^2

so acceleration will be 3 m/s^2

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Which of the following measurements involve a direction
insens350 [35]

Answer:

I think it is Velocity idk but does it hurt to try

8 0
3 years ago
A post is wrapped two full turns around with a belt. The tension in the belt is 7500 N by exerting a force of 150 N on its free
ira [324]

Answer:

Coefficient of friction is

Ū = 0.31

Explanation:

T2 = T1* e^(ūơ)

Where T2 = 7500n = tension in the belt, T1 = 150n = reaction force,

ū = coefficient of friction

Ơ = 2pai * N

Where N = number of turns = 2

Ơ = 4pai

7500 = 150e^(ū*4pai)

50 = e^(ū *4pai)

lin 50 = 4pai * ū

Ū = 3.91/4pai

Ū = 0.31

4 0
3 years ago
A block is thrown with an initial velocity of 30.0 m/s at an angle of 25.0o above the horizontal. What is the highest elevation
Serga [27]

The highest elevation reached by the ball in its trajectory is 16.4 m.

To find the answer, we need to know about the maximum height reached in a projectile.

What's the mathematical expression of the maximum height reached in a projectile motion?

  • The maximum height= U²× sin²(θ)/g
  • U= initial velocity, θ= angle of projectile with horizontal and g= acceleration due to gravity

What's the maximum height reached by a block that is thrown with an initial velocity of 30.0 m/s at an angle of 25° above the horizontal?

  • Here, U = 30.0 m/s and θ= 25°
  • Maximum height= 30²× sin²(25)/9.8

= 16.4m

Thus, we can conclude that the highest elevation reached by the ball in its trajectory is 16.4 m.

Learn more about the projectile motion here:

brainly.com/question/24216590

#SPJ4

3 0
2 years ago
Rank the six combinations of electric charges on the basis of the electric force acting on q1. Define forces pointing to the rig
goldenfox [79]

Answer:

Largest

[q1=+1nC, q2=-1nC, q3=-1nC] & [q1=-1nC, q2=+1nC, q3=+1nC]

[q1=+1nC, q2=-1nC, q3=+1nC]

[q1=+1nC, q2=+1nC, q3=-1nC]

Smallest

[q1=+1nC, q2=+1nC, q3=+1nC] & [q1=-1nC, q2=-1nC, q3=-1nC]

Explanation:

5 0
3 years ago
A block rests on a ?at plate that executes vertical simple harmonic motion with a period of 0.58s.
SVETLANKA909090 [29]

Answer:

maximum amplitude  = 0.08 m

Explanation:

Given that

Time period T= 0.58 s

acceleration of gravity g= 9.8 m/s²

We know that time period of simple harmonic motion given as

T = 2π/ω

0.58 = 2π/ω

ω = 10.83rad/s

ω=angular frequency

Lets take amplitude = A

The maximum acceleration given as

a= ω² A

The maximum acceleration should be equal to g ,then block does not separate

a= ω² A

9.8 =  10.83² A

A = 0.08m

maximum amplitude  = 0.08 m

8 0
3 years ago
Read 2 more answers
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