Answer:
a.) L = 2.64 kgm^2/s
b.) V = 4.4 m/s
Explanation: Jessica stretches her arms out 0.60 m from the center of her body. This will be considered as radius.
So,
Radius r = 0.6 m
Mass M = 2 kg
Velocity V = 1.1 m/s
Angular momentum L can be expressed as;
L = MVr
Substitute all the parameters into the formula
L = 2 × 1.1 × 0.6 = 1.32kgm^2s^-1
the combined angular momentum of the masses will be 2 × 1.32 = 2.64 kgm^2s-1
b. If she pulls her arms into 0.15 m,
New radius = 0.15 m
Using the same formula again
L = 2( MVr)
2.64 = 2( 2 × V × 0.15 )
1.32 = 0.3 V
V = 1.32/0.3
V = 4.4 m/s
Her new linear speed will be 4.4 m/s
Answer:
Take whatever you weigh in pounds and divide by 2.205.
Explanation:
Because weight is a measure of the force you exert on the earth, with some simple manipulation of Newton's second law we can get your mass in kilograms. 2.205 is just a nice constant that does that for you, but the more in-depth version is that
F = ma
The equation for weight is thus
W = mg, where W is your weight in pounds, m is your mass, and g is the acceleration due to gravity (9.80 m/s^2)
Thus, your mass in kilograms is m = W / g.
Hello There!
From what i know, gravitational force increases if the mass is increased.
If the mass is being decreased, then i assume it will be B. Decreases.
Hope This Helps You!
Good Luck :)
- Hannah ❤
Answer:
a)0.22 m/s².
Explanation:
Given that
Net force ,F= 6.8 N
mass ,m = 31 kg
From the second law of Newton's
F = m a ---------------1
Where
F=Net force ,m=mass
a=Acceleration
Now by putting the values in the equation 1
F = m a
6.8 = 31 x a
Therefore the acceleration of the scooter will be 0.22 m/s².
The answer will be "a".
a)0.22 m/s².
Let 
be the speed of the helicopter in still air. Let 
be the speed of the wind. Then, from the given information,
Adding the above 2 equations,
The speed of the helicopter in still air 
