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stiks02 [169]
3 years ago
9

NEED HELP !!!!!

Mathematics
1 answer:
Roman55 [17]3 years ago
8 0
Given that <span>x represent the number of years since the first census was taken, this means that the first time census was taken was counted as x = 0.

Given that </span>the first time a census was taken in Michele Corners, the population was 1772.

Therefore, <span>the coordinates of the point that contains the ­y-intercept is (0, 1772)</span>
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The sum of 6 consecutive odd numbers is 204. What is the fourth number in this sequence?
Korolek [52]

204 /6 = 34

29 +31 +33 + 35 +37 +39 = 207

4th number = 35

6 0
3 years ago
Read 2 more answers
2|3x + 5| = -10 how break it down
iren2701 [21]
2|3x + 5| = -10 . Divide both sides by 2:

|3x + 5| = -5 ===>3x+5=-5 & -3x-5=-5 In both cases x=0 
6 0
3 years ago
A type is typically makes an error on one out of every 21 documents they complete if the typist can complete 120 documents an ho
motikmotik
<span>Answer: 21 document= 1 error 120 document= 1 hour in three and a half hours= 21 mistakes</span>
8 0
3 years ago
A store uses the expression –2p + 50 to model the number of backpacks it sells per day, where the price, p, can be anywhere from
Rus_ich [418]
Revenue = price * number of backpacks
number of backpacks = -2p + 50

p = 9 ; -2(9) + 50 = -18 + 50 = 32
revenue = 9 * 32 = 288

p = 12 ; -2(12) + 50 = -24 + 50 = 26
revenue = 12 * 26 = 312

<u>p = 12.50 ; -2(12.50) + 50 = -25 + 50 = 25</u>
<u>revenue = 12.50 * 25 = 312.50</u>   GIVES THE MAXIMUM REVENUE

p = 15 ; -2(15) + 50 = -30 + 50 = 20
revenue = 15 * 20 = 300
8 0
3 years ago
Read 2 more answers
Use the "mixed partials" check to see if the following differential equation is exact. If it is exact find a function F(x,y) who
Arturiano [62]

We have

(-3xy^2+y)_y=--6xy+1

and

(-3x^2y+x)_x=-6xy+1

so the equation is indeed exact. So we want to find a function F(x,y)=C such that

F_x=-3xy^2+y

F_y=-3x^2y+x

Integrating both sides of the first equation wrt x gives

F(x,y)=-\dfrac32x^2y^2+xy+f(y)

Differentiating both sides wrt y gives

F_y=-3x^2y+x=-3x^2y+x+f_y\implies f_y=0\implies f(y)=C

So we have

F(x,y)=-\dfrac32x^2y^2+xy+C=C

or

F(x,y)=\boxed{-\dfrac32x^2y^2+xy=C}

3 0
3 years ago
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