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3 years ago

Bett you guys can help meif you do tho you don’t have corona ✌

Mathematics

1 answer:

blsea [12.9K]3 years ago

7 0

Guess I have corona....................

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What is the answer to this problem?

blagie [28]

Answer:

3/16

Step-by-step explanation:

Multiply both denominators and numerators together, which creates the new fraction.

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4 years ago

at Monica's used cars,the sales staff set a goal of $25,500 in sales each week. The sales for three weeks were $28,288; $25,369;

lora16 [44]

25.369 did not meet her goal for the week

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3 years ago

What is 5/12 times blank equals 1

Alisiya [41]

Answer:

12/5 or 2.4 or 2 and 2/5

Step-by-step explanation:

1 / 5/12

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3 years ago

NEED HELP ASAP WILL GIVE BRAINLY

Anon25 [30]

Answer:

15.7

Step-by-step explanation

hard to explain

5 0

3 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately 63.7 ft.

The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately 63.7 ft.

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately 298.35 ft.

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately 708.92 ft.

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ 98.211 ft./s

Learn more here:

brainly.com/question/18591940

8 0

2 years ago